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A router uses the following routing table:
packet bearing a destination address 144.16.68.117 arrives at the router. On which interface will it be forwarded?
  • a)
    eth0
  • b)
    eth1
  • c)
    eth2
  • d)
    eth3
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A router uses the following routing table:packet bearing a destination...
Firstly start with Longest mask
144. 16 . 68 .117 = 144. 16. 68. 01110101 AND 255.255.255.224 = 255.255.255. 11100000 = 144.16.68.96 (Not matching with Destination)
Now, take 255. 255. 255. 0
144.16. 68.117 AND 255.255.255.0 = 144.16.68.0 (matched) So,interface chosen is eth2 OPTION (C).
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A router uses the following routing table:packet bearing a destination...
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A router uses the following routing table:packet bearing a destination...
Firstly start with Longest mask
144. 16 . 68 .117 = 144. 16. 68. 01110101 AND 255.255.255.224 = 255.255.255. 11100000 = 144.16.68.96 (Not matching with Destination)
Now, take 255. 255. 255. 0
144.16. 68.117 AND 255.255.255.0 = 144.16.68.0 (matched) So,interface chosen is eth2 OPTION (C).
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A router uses the following routing table:packet bearing a destination address 144.16.68.117 arrives at the router. On which interface will it be forwarded?a)eth0b)eth1c)eth2d)eth3Correct answer is option 'C'. Can you explain this answer?
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