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At which of the following temperature would the molecules of a gas have twice the average kinetic energy they have at 20°C (in °C)
    Correct answer is '313'. Can you explain this answer?
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    At which of the following temperature would the molecules of a gas hav...
    E ∝ T


    ⇒ T2 = 293 × 2 = 586 K
    ⇒ T2 = 313 °C
    The correct answer is: 313
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    At which of the following temperature would the molecules of a gas hav...
    To find the temperature at which the molecules of a gas have twice the average kinetic energy they have at 20°C, we can use the equation for average kinetic energy:

    Average Kinetic Energy = (3/2) * k * T

    Where:
    - Average Kinetic Energy is the average kinetic energy of the gas molecules
    - k is the Boltzmann constant (k = 1.38 x 10^-23 J/K)
    - T is the temperature in Kelvin

    Let's denote the temperature at which the molecules have twice the average kinetic energy as T2. We can set up the following equation:

    (3/2) * k * T2 = 2 * (3/2) * k * (20 + 273.15)

    Simplifying the equation:

    T2 = 2 * (20 + 273.15)

    T2 = 2 * 293.15

    T2 = 586.3 K

    Therefore, the temperature at which the molecules of a gas have twice the average kinetic energy they have at 20°C is 586.3 Kelvin.
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    At which of the following temperature would the molecules of a gas have twice the average kinetic energy they have at 20°C (in °C)Correct answer is '313'. Can you explain this answer?
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