A book of weight 20N is pressed between two hands and each hand exerts...
Weight of book =friction between hand and book
mg=in
20=u (40+40)
20=u (80)
u=20/80
u=0.25
A book of weight 20N is pressed between two hands and each hand exerts...
Given:
- Weight of the book = 20N
- Force exerted by each hand = 40N
To find:
- Coefficient of friction
Explanation:
When the book just starts to slide down, the force of friction acting on the book is equal to the maximum static friction.
The maximum static friction can be calculated using the formula:
Maximum static friction (F_s) = coefficient of friction (μ_s) * normal force (N)
The normal force (N) is equal to the weight of the book, which is 20N.
Therefore, the maximum static friction is given by:
F_s = μ_s * N
Given that each hand exerts a force of 40N, the total force applied on the book is 80N.
Since the book is not moving vertically, the vertical forces must be balanced. Therefore, the normal force (N) is equal to the weight of the book, which is 20N.
Calculating the Coefficient of Friction:
To find the coefficient of friction, we can rearrange the equation for maximum static friction:
F_s = μ_s * N
μ_s = F_s / N
Substituting the values, we have:
μ_s = 80N / 20N
μ_s = 4
Therefore, the coefficient of friction (μ_s) is 4.
Conclusion:
The coefficient of friction between the book and the hands is 4. This means that the frictional force between the book and the hands is four times the normal force.
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