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A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM 
that is required to accommodate the Truth table is 
. Write the values of M and N.
that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer?
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Verified Answer
A ROM is used to store the Truth table for a binary multiple unit that...
A is 4 bit binary no A4A3A2A1
B is 4 bit binary no B4B3B2B1
M is result of multiplication M8M7M6M5M4M3M2M1 [check biggest no 1111 x 1111 =11100001]
So 4 bit of A 4 bit of B
input will consist of 8 bit need address 00000000 to 11111111 = 28 address
output will be of 8 bits
so memory will be of
M = 256 , N = 8
B is 4 bit binary no B4B3B2B1
M is result of multiplication M8M7M6M5M4M3M2M1 [check biggest no 1111 x 1111 =11100001]
So 4 bit of A 4 bit of B
input will consist of 8 bit need address 00000000 to 11111111 = 28 address
output will be of 8 bits
so memory will be of
M = 256 , N = 8
Most Upvoted Answer
A ROM is used to store the Truth table for a binary multiple unit that...
A is 4 bit binary no A4A3A2A1
B is 4 bit binary no B4B3B2B1
M is result of multiplication M8M7M6M5M4M3M2M1 [check biggest no 1111 x 1111 =11100001]
So 4 bit of A 4 bit of B
input will consist of 8 bit need address 00000000 to 11111111 = 28 address
output will be of 8 bits
so memory will be of
M = 256 , N = 8
B is 4 bit binary no B4B3B2B1
M is result of multiplication M8M7M6M5M4M3M2M1 [check biggest no 1111 x 1111 =11100001]
So 4 bit of A 4 bit of B
input will consist of 8 bit need address 00000000 to 11111111 = 28 address
output will be of 8 bits
so memory will be of
M = 256 , N = 8
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Community Answer
A ROM is used to store the Truth table for a binary multiple unit that...
A is 4 bit binary no A4A3A2A1
B is 4 bit binary no B4B3B2B1
M is result of multiplication M8M7M6M5M4M3M2M1 [check biggest no 1111 x 1111 =11100001]
So 4 bit of A 4 bit of B
input will consist of 8 bit need address 00000000 to 11111111 = 28 address
output will be of 8 bits
so memory will be of
M = 256 , N = 8
B is 4 bit binary no B4B3B2B1
M is result of multiplication M8M7M6M5M4M3M2M1 [check biggest no 1111 x 1111 =11100001]
So 4 bit of A 4 bit of B
input will consist of 8 bit need address 00000000 to 11111111 = 28 address
output will be of 8 bits
so memory will be of
M = 256 , N = 8
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A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer?
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A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer?.
A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer?.
Solutions for A ROM is used to store the Truth table for a binary multiple unit that will multiply two 4-bit numbers. The size of the ROM that is required to accommodate the Truth table is . Write the values of M and N.Correct answer is '8'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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