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A satellite is moving with a constant speed 'V' in a circular orbit about the earth. An object of mass 'm' is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy of the object is 
[jee 2011]
  • a)
     mV2
  • b)
    mV2
  • c)
    mV2
  • d)
     2mV2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A satellite is moving with a constant speed 'V' in a circular ...
Orbital speed = √Gm/r
Escape speed = √2Gm/r
So, KE is 2 times
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Most Upvoted Answer
A satellite is moving with a constant speed 'V' in a circular ...
Orbital speed is √Gm/r
whereas for escape speed is √2Gm/r
so k.e.goes to 2 times
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Community Answer
A satellite is moving with a constant speed 'V' in a circular ...
1/2mv2
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A satellite is moving with a constant speed 'V' in a circular orbit about the earth. An object of mass 'm' is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy of the object is[jee 2011]a)mV2b)mV2c)mV2d)2mV2Correct answer is option 'B'. Can you explain this answer?
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