The base (or radix) of the number system such that the following equat...
Let ‘x’ be the base or radix of the number system .
The equation is : (3.x2+1.x1+2.x0) /(2.x1 +0.x0) =1.x1 +3.x0 +1.x-1
=>(3.x2+x +2) /(2.x) =x +3 +1/x
=>(3.x2+x +2) /(2.x) =(x2 +3x +1) /x
By solving above quadratic equation you will get x=0 and x=5
As base or radix of a number system cannot be zero, here x = 5
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The base (or radix) of the number system such that the following equat...
Solution:
To find out the base of the number system, we need to convert the given numbers into the decimal system.
Given: 312/20 = 13.1
Step 1: Convert the integer part of the quotient into the decimal system.
The integer part of the quotient is 13, which is already in the decimal system.
Step 2: Convert the fractional part of the quotient into the decimal system.
The fractional part of the quotient is 0.1.
0.1 = 1/10
Step 3: Convert the dividend (312) and divisor (20) into the decimal system.
312 = 3 * 100 + 1 * 10 + 2 * 1 = 302
20 = 2 * 10 + 0 * 1 = 20
Step 4: Write the equation in the decimal system.
302/20 = 13.1
Step 5: Find the base of the number system.
Let the base of the number system be 'b'.
We can write 302 in terms of base 'b' as:
302 = 3 * b^2 + 0 * b + 2 * 1 = 3b^2 + 2
We can write 20 in terms of base 'b' as:
20 = 2 * b + 0 * 1 = 2b
Substituting these values in the equation, we get:
(3b^2 + 2)/(2b) = 13.1
Multiplying both sides by 2b, we get:
3b^2 + 2 = 26.2b
3b^2 - 26.2b + 2 = 0
Using the quadratic formula, we get:
b = (26.2 ± sqrt(26.2^2 - 4 * 3 * 2))/(2 * 3)
b = (26.2 ± sqrt(664.84 - 24))/(6)
b = (26.2 ± sqrt(640.84))/(6)
b = (26.2 ± 25.3)/(6)
b = 5.25 or b = 0.17
Since the base of the number system cannot be less than 2, the only valid solution is b = 5.
Therefore, the base of the number system such that the equation 312/20 = 13.1 holds is 5.