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A solution of colourless salt H on boiling with excess NaOH produces a non-flammable gas. The gas evolution ceases after sometime. Upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless salt (s) H is (are)
- a)NH4NO3
- b)NH4NO2
- c)NH4Cl
- d)(NH4)2SO4
Correct answer is option 'A,B'. Can you explain this answer?
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Verified Answer
A solution of colourless salt H on boiling with excess NaOH produces a...
When ammonium salt NH4NO3 or NH4NO2 (ammonium salts are colourless) is boiled with excess of NaOH, ammonia (NH3) gas is evolved as follows:
NH4NO2 + NaOH → NaNO2 + NH3 + H2O
NH4NO3 + NaOH → NaNO3 + NH3 + H2O
NH4NO3 + NaOH → NaNO3 + NH3 + H2O
The NH3 gas evolved is non-flammable gas.
When the gas evolution ceases we are left with NaNO2 or NaNO3 in solution.
These salts get reduced when Zn is added to this solution containing salt (NaNO2 or NaNO3) and excess NaOH and NH3 gas is evolve.
When the gas evolution ceases we are left with NaNO2 or NaNO3 in solution.
These salts get reduced when Zn is added to this solution containing salt (NaNO2 or NaNO3) and excess NaOH and NH3 gas is evolve.
Thus the colourless salt [H] is either NH4NO2 or NH4NO3.
Thus (a) and (b) are correct answers. [NOTE : NaCl formed has no reaction with NaOH]
Thus (a) and (b) are correct answers. [NOTE : NaCl formed has no reaction with NaOH]
Most Upvoted Answer
A solution of colourless salt H on boiling with excess NaOH produces a...
Solution:
Identification of Salt H
When salt H is boiled with excess NaOH, a non-flammable gas is evolved which ceases after some time. This indicates that salt H is an ammonium salt because ammonium salts on heating with excess NaOH evolve ammonia gas which is non-flammable. Therefore, the possible options for salt H are:
a) NH4NO3
b) NH4NO2
c) NH4Cl
d) (NH4)2SO4
Identification of Gas Evolved
When excess NaOH is added to salt H, ammonia gas is evolved which ceases after some time. This indicates that all the ammonium ions have been converted to ammonia gas. Therefore, the gas evolved is ammonia gas.
Zinc Dust Test
When zinc dust is added to the same solution, the gas evolution restarts. This test confirms the presence of ammonium ions in the solution because zinc dust reduces ammonium ions to ammonia gas.
Conclusion
Based on the above observations, salt H could be either NH4NO3 or NH4NO2 because both these salts on heating with excess NaOH evolve ammonia gas which ceases after some time, and on addition of zinc dust, the gas evolution restarts.
Identification of Salt H
When salt H is boiled with excess NaOH, a non-flammable gas is evolved which ceases after some time. This indicates that salt H is an ammonium salt because ammonium salts on heating with excess NaOH evolve ammonia gas which is non-flammable. Therefore, the possible options for salt H are:
a) NH4NO3
b) NH4NO2
c) NH4Cl
d) (NH4)2SO4
Identification of Gas Evolved
When excess NaOH is added to salt H, ammonia gas is evolved which ceases after some time. This indicates that all the ammonium ions have been converted to ammonia gas. Therefore, the gas evolved is ammonia gas.
Zinc Dust Test
When zinc dust is added to the same solution, the gas evolution restarts. This test confirms the presence of ammonium ions in the solution because zinc dust reduces ammonium ions to ammonia gas.
Conclusion
Based on the above observations, salt H could be either NH4NO3 or NH4NO2 because both these salts on heating with excess NaOH evolve ammonia gas which ceases after some time, and on addition of zinc dust, the gas evolution restarts.
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A solution of colourless salt H on boiling with excess NaOH produces a non-flammable gas. The gas evolution ceases after sometime. Upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless salt (s) H is (are)a)NH4NO3b)NH4NO2c)NH4Cld)(NH4)2SO4Correct answer is option 'A,B'. Can you explain this answer?
Question Description
A solution of colourless salt H on boiling with excess NaOH produces a non-flammable gas. The gas evolution ceases after sometime. Upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless salt (s) H is (are)a)NH4NO3b)NH4NO2c)NH4Cld)(NH4)2SO4Correct answer is option 'A,B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solution of colourless salt H on boiling with excess NaOH produces a non-flammable gas. The gas evolution ceases after sometime. Upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless salt (s) H is (are)a)NH4NO3b)NH4NO2c)NH4Cld)(NH4)2SO4Correct answer is option 'A,B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of colourless salt H on boiling with excess NaOH produces a non-flammable gas. The gas evolution ceases after sometime. Upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless salt (s) H is (are)a)NH4NO3b)NH4NO2c)NH4Cld)(NH4)2SO4Correct answer is option 'A,B'. Can you explain this answer?.
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