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Consider the binary code that consists of only four valid codewords as given below: 00000, 01011, 10101, 11110
Let the minimum Hamming distance of the code p and the maximum number of erroneous bits that can be corrected by the code be q. Then the values of p and q are
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Consider the binary code that consists of only four valid codewords as...
00000(code1),01011(code2),10101(code3),11110(code4)
Haming distance = min of all hamming distances.
which is 3 b/w (code1) and (code2) so p = 3
Now to correct d bit error we need hamming distance = 2d+1
so 2d+1 = 3 will gives d= 1.
A is answer
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Consider the binary code that consists of only four valid codewords as given below: 00000, 01011, 10101, 11110Let the minimum Hamming distance of the code p and the maximum number of erroneous bits that can be corrected by the code be q. Then the values of p and q area)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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