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For any integer P greater than 1, P! denotes the product of all the integers from 1 to P, inclusive. In how many ways can 9! be
expressed as a product of 2 positive integers?
  • a)
    36
  • b)
    72
  • c)
    79
  • d)
    80
  • e)
    160
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
For any integer P greater than 1, P! denotes the product of all the in...
Given:
P > 1
P! = 1 x 2 x 3…x P
 
To Find
# of ways
in which 9! can be written
as a x b , where a, b are integers > 0
Approach:
1. Note the nature of numbers a,b in the product . a x b.
a,b are both factors of 9!.
Let’s take a simple example to understand the above application. Let’s take the number 6.
Its factors are – 1, 2, 3, 6 - i.e. 4 factors
It can be expressed as product of two numbers as follows
1 x 6
2 x 3
Working out:
9! can be expressed as a product of two positive numbers in 80 ways. Choice D is the correct answer.
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For any integer P greater than 1, P! denotes the product of all the integers from 1 to P, inclusive. In how many ways can 9! beexpressed as a product of 2 positive integers?a)36b)72c)79d)80e)160Correct answer is option 'D'. Can you explain this answer?
Question Description
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