Gravitational force which acts on 1 kg isa)9.8 Nb)1/9.8 Nc)980 Nd)none...
Gravitational force is the force of attraction between two objects with mass. It is the force that gives weight to physical objects and is responsible for holding planets, stars, and galaxies together. In this question, we are asked to determine the gravitational force acting on a 1 kg object.
The formula to calculate the gravitational force (F) between two objects is given by Newton's law of universal gravitation:
F = G * (m1 * m2) / r^2
Where:
- F is the gravitational force
- G is the gravitational constant (approximately 6.67 × 10^-11 Nm^2/kg^2)
- m1 and m2 are the masses of the two objects
- r is the distance between the centers of the two objects
In this case, we have a 1 kg object, so m1 = 1 kg. The force we are looking for is the force acting on this object, so we assume m2 is the mass of the Earth. The mass of the Earth is approximately 5.98 × 10^24 kg. The distance between the object and the center of the Earth is not given, but we can assume it is the radius of the Earth, which is approximately 6,371 km or 6,371,000 meters.
Substituting the values into the formula:
F = (6.67 × 10^-11 Nm^2/kg^2) * (1 kg * 5.98 × 10^24 kg) / (6,371,000)^2
Simplifying the equation:
F = (6.67 × 10^-11 Nm^2/kg^2) * (5.98 × 10^24 kg) / (6,371,000)^2
F = 9.8 N
Therefore, the gravitational force acting on a 1 kg object is 9.8 N. This means that if we were to lift a 1 kg object against gravity, we would need to exert a force of 9.8 N in the opposite direction in order to counteract the gravitational force.
Gravitational force which acts on 1 kg isa)9.8 Nb)1/9.8 Nc)980 Nd)none...
To covert kg to N , we have to multiply the kg value by 9.8 . So 1x9.8=9.8. hence the answer A is correct