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On heating glycerol with excess of HI gives
  • a)
    allyl iodide
  • b)
    isopropyl iodide
  • c)
    propylene
  • d)
    1 ,2,3-tri iodopropane
Correct answer is option 'B'. Can you explain this answer?
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Explanation:

Heating glycerol with excess of HI:
- When glycerol is heated with excess of HI, it undergoes dehydration reaction.
- The reaction proceeds via an E1 mechanism, where glycerol loses water molecule to form an alkene.

Formation of isopropyl iodide (2-iodopropane):
- The alkene formed from glycerol is propene.
- Propene reacts with excess of HI to form isopropyl iodide (2-iodopropane).
- The mechanism involves the addition of HI across the double bond in propene to form the desired product.

Correct answer:
- The correct product obtained from heating glycerol with excess of HI is isopropyl iodide (2-iodopropane), hence option 'B' is correct.
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On heating glycerol with excess of HI givesa)allyl iodideb)isopropyl iodidec)propylened)1 ,2,3-tri iodopropaneCorrect answer is option 'B'. Can you explain this answer?
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