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The coordination number and the oxidation state of the element ‘E’ in the complex
[E (en)2 (C2O4)]NO2 (where (en) is ethylene diamine) are, respectively,
  • a)
    6 and 2
  • b)
    4 and 2
  • c)
    4 and 3
  • d)
    6 and 3
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The coordination number and the oxidation state of the element ‘...
In the given complex we have two bidentate ligands (i.e en and  C2O4), so coordination number of E is 6 (2 × 2 + 1 × 2 = 6)
Let the oxidation state of E in complex be x, then [x + (–2) = 1]  or   x – 2 = 1 or x = + 3, so its oxidation state is + 3
Thus option (d) is correct.
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The coordination number and the oxidation state of the element ‘E’ in the complex[E (en)2 (C2O4)]NO2 (where (en) is ethylene diamine) are, respectively,a)6 and 2b)4 and 2c)4 and 3d)6 and 3Correct answer is option 'D'. Can you explain this answer?
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The coordination number and the oxidation state of the element ‘E’ in the complex[E (en)2 (C2O4)]NO2 (where (en) is ethylene diamine) are, respectively,a)6 and 2b)4 and 2c)4 and 3d)6 and 3Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The coordination number and the oxidation state of the element ‘E’ in the complex[E (en)2 (C2O4)]NO2 (where (en) is ethylene diamine) are, respectively,a)6 and 2b)4 and 2c)4 and 3d)6 and 3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coordination number and the oxidation state of the element ‘E’ in the complex[E (en)2 (C2O4)]NO2 (where (en) is ethylene diamine) are, respectively,a)6 and 2b)4 and 2c)4 and 3d)6 and 3Correct answer is option 'D'. Can you explain this answer?.
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