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In an a.c. circuit voltage V and current i are given by V = 100 sin 100 t volts, i = 100 sin (100t + p/3) mA. The power dissipated in the circuit is :
  • a)
    104 W
  • b)
    10 W
  • c)
     2.5 W
  • d)
    5 W
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In an a.c. circuit voltage V and current i are given by V = 100 sin 10...
Vrms = 100/√2 V
Irms = 100/√2 mA
= 10-1/√2 A
π/3 = 30º
Average power = Vrms×Irms× cos
= (100/√2)×(10-1√2)× cos 30º
= 10/2×(1/2)
= 10/4
= 2.5W
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Most Upvoted Answer
In an a.c. circuit voltage V and current i are given by V = 100 sin 10...
Vrms = 100/√2 V
Irms = 100/√2 mA
= 10⁻¹/√2 A
π/3 = 30º
Average power = Vrms×Irms× cos
= (100/√2)×(10⁻¹√2)× cos 30º
= 10/2×(1/2)
= 10/4
= 2.5W
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Community Answer
In an a.c. circuit voltage V and current i are given by V = 100 sin 10...
Vrms = 100/√2 V
Irms = 100/√2 mA
= 10-1/√2 A
π/3 = 30º
Average power = Vrms×Irms× cos
= (100/√2)×(10-1√2)× cos 30º
= 10/2×(1/2)
= 10/4
= 2.5W
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In an a.c. circuit voltage V and current i are given by V = 100 sin 100 t volts, i = 100 sin (100t + p/3) mA. The power dissipated in the circuit is :a)104Wb)10 Wc)2.5 Wd)5 WCorrect answer is option 'C'. Can you explain this answer?
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