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In the xy-plane, Region R is bounded by the line segments with equations, 2x + |4y| = 20 and x=0, whereas Region P is bounded by the line segments with equations |4x| + 2y = 20 and y = 0. If the function A(B) is defined as the area of Region B, what is the value of |A(P) – 2A(R)|?
  • a)
    0
  • b)
    25
  • c)
    50
  • d)
    75
  • e)
    100
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In the xy-plane, Region R is bounded by the line segments with equatio...
Given
  • Region R is bounded by
    • 2x + |4y| = 20 and
    • x=0, whereas
  • Region P is bounded by
    • |4x| + 2y = 20 and
    • y = 0
  • A(B) = area of Region B
To Find: |A(P) – 2A(R)|?
  • We need to find the area of regions P and R to answer the question
Approach
  • Region R
    • For finding the area of region R, we need to draw the following line segments:
      • x = 0
      • 2x +4|y| = 20. As we are given |y|, the value of |y| will depend on the value of y
        • If y ≥0, then |y| = y.
          • So, we have equation of the line segment as 2x + 4y = 20, i.e. x + 2y = 10 and
        • If y < 0, then |y| = -y.
          • So, we have equation of the line segment as 2x – 4y = 20, i.e. x – 2y = 10
    • Once we draw these line segments, we will find the area of the region bounded by the line segments using standard formulas.
  • Region P
    • For finding the area of region R, we need to draw the following line segments:
      • y = 0
      • |4x| + 2y = 20. As we are given |x|, the value of |x| will depend on the value of x.
        • If x ≥0, then |x| = x.
          • So, we have the equation as 4x + 2y = 20, i.e. 2x + y = 10 and
        • If x < 0, then |x| = -x.
          • So, we have the equation of the line segment as 4x – 2y = -20, i.e. 2x – y = -10
  • Once we draw these line segments, we will find the area of the region bounded by the line segments using standard formulas
Working out
1. Finding A(R)
a. Assuming y-axis to be the base, we have EF = 5 – (-5) = 10
b. Height = x-coordinate of point D = 10
c. Area of region R = ½ * 10 * 10 = 50
d. A(R) = 50……. (1)
2. Finding A(P)
a. Assuming x-axis to be the base, we have BD = 5 – (-5) = 10
b. Height = y-coordinate of point A = 10
c. Area of region P = ½ * 10 * 10 = 50
d. A(P) = 50…….(2)
3. Using (1) and (2), we have
a. |A(P) – 2A(R)| = | 50 – 2*50| = |-50| = 50
Answer: C
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In the xy-plane, Region R is bounded by the line segments with equations, 2x + |4y| = 20 and x=0, whereas Region P is bounded by the line segments with equations |4x| + 2y = 20 and y = 0. If the function A(B) is defined as the area of Region B, what is the value of |A(P) – 2A(R)|?a)0b)25c)50d)75e)100Correct answer is option 'C'. Can you explain this answer?
Question Description
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