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A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.
Q.
When the salt A is heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas is
- a)chlorine
- b)HCI
- c)Both (a) and (b)
- d)SO2 and HCI
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas whic...
Chloride salt produce colourless HCI vapours with conc. H2SO4 and these become dense due to NH4Cl on exposure to ammonia.
Most Upvoted Answer
A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas whic...
Explanation:
Salt A, when heated with K2Cr2O7 and cone. H2SO4, liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4, a gas C is evolved which turns a starch-iodide paper blue.
From the given information, we can conclude that salt A contains both Cl- and H+ ions. When heated with K2Cr2O7 and cone. H2SO4, it undergoes oxidation and reduction reactions, resulting in the evolution of a gas which is absorbed in NaOH solution. The yellow color of the NaOH solution indicates the formation of Cl2 gas.
The acidic solution obtained after the absorption of gas in NaOH is then treated with acetic acid and lead acetate solution. The yellow precipitate B formed is PbCrO4, which confirms the presence of Cl- ions in salt A.
When salt A is heated with MnO2 and cone. H2SO4, it undergoes a redox reaction, resulting in the evolution of a gas C. This gas is Cl2, which turns a starch-iodide paper blue.
When salt A is heated with cone. H2SO4, a colorless gas is evolved. This gas gives dense fumes when exposed to ammonia. The gas is HCl, which confirms the presence of H+ ions in salt A.
Therefore, the correct answer is option 'B', which states that the gas evolved is HCl.
Salt A, when heated with K2Cr2O7 and cone. H2SO4, liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4, a gas C is evolved which turns a starch-iodide paper blue.
From the given information, we can conclude that salt A contains both Cl- and H+ ions. When heated with K2Cr2O7 and cone. H2SO4, it undergoes oxidation and reduction reactions, resulting in the evolution of a gas which is absorbed in NaOH solution. The yellow color of the NaOH solution indicates the formation of Cl2 gas.
The acidic solution obtained after the absorption of gas in NaOH is then treated with acetic acid and lead acetate solution. The yellow precipitate B formed is PbCrO4, which confirms the presence of Cl- ions in salt A.
When salt A is heated with MnO2 and cone. H2SO4, it undergoes a redox reaction, resulting in the evolution of a gas C. This gas is Cl2, which turns a starch-iodide paper blue.
When salt A is heated with cone. H2SO4, a colorless gas is evolved. This gas gives dense fumes when exposed to ammonia. The gas is HCl, which confirms the presence of H+ ions in salt A.
Therefore, the correct answer is option 'B', which states that the gas evolved is HCl.
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A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer?
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A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer?.
A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer?.
Solutions for A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A salt A when heated with K2Cr2O7 and cone. H2SO4 liberates a gas which is absorbed in NaOH solution. The NaOH solution turns yellow. When this solution is acidified with acetic acid and lead acetate solution is added, a yellow precipitate B is formed. When A is mixed with MnO2 and heated with cone. H2SO4 , a gas C is evolved which turns a starch-iodide paper blue.Q.When the salt Ais heated with cone. H2SO4, colourless gas is evolved which gives dense fumes when exposed with ammonia. The gas isa)chlorineb)HCIc)Both (a) and (b)d)SO2 and HCICorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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