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A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.
It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.
The compound contains a total of six aliylic hydrogen atoms.
The carbon atom that holds the Br has one H attached to it.
Working Space
When compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.
It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.
The compound contains a total of six aliylic hydrogen atoms.
The carbon atom that holds the Br has one H attached to it.
Working Space
When compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.
Q.
If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?
- a)It will have no stereogenic centre i.e. it will not show stereoisomerism
- b)It will show stereoisomerism but cannot be resolved into enantiomers
- c)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for E
- d)None of the above appropriately applies to E
Correct answer is option 'B'. Can you explain this answer?
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A chemist isolated a compound A with molecular formula C7H13Br. A unde...
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Explanation:
Statement: It will show stereoisomerism but cannot be resolved into enantiomers
- Compound E, which is produced as a major product by E2 elimination reaction, is a compound with more than one stereogenic center. This means it will have stereoisomers.
- However, since there are more than two different structures of stereoisomers that can be drawn for compound E, it cannot be resolved into enantiomers.
- This implies that compound E will show stereoisomerism but cannot be resolved into enantiomers.
Therefore, option 'B' is the correct statement consistent with compound E.
Statement: It will show stereoisomerism but cannot be resolved into enantiomers
- Compound E, which is produced as a major product by E2 elimination reaction, is a compound with more than one stereogenic center. This means it will have stereoisomers.
- However, since there are more than two different structures of stereoisomers that can be drawn for compound E, it cannot be resolved into enantiomers.
- This implies that compound E will show stereoisomerism but cannot be resolved into enantiomers.
Therefore, option 'B' is the correct statement consistent with compound E.
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A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer?
Question Description
A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer?.
A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer?.
Solutions for A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the —OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?a)It will have no stereogenic centre i.e. it will not show stereoisomerismb)It will show stereoisomerism but cannot be resolved into enantiomersc)It will have more than one stereogenic centres and more than two, different structures of stereoisomers can be drawn for Ed)None of the above appropriately applies to ECorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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