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Two small circular ofifices of diameters d1 and d2 are placed on one side of a tank at depths of 25 cm and 1 m respectively below a constantsurface of water. If the discharges through theorifice are the same, then the ratio of the diameters d1 and d2 will be
  • a)
    1 :2
  • b)
    1: √2
  • c)
    √2 :1
  • d)
    2 : 1
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two small circular ofifices of diameters d1 and d2 are placed on one s...
Solution:

Given,
d1 = diameter of the first orifice = ?
d2 = diameter of the second orifice = ?
h1 = depth of the first orifice = 25 cm = 0.25 m
h2 = depth of the second orifice = 1 m

Let us consider the Bernoulli's equation between section 1 and 2 as shown in the figure below.



Where,
v1 and v2 are the velocities of water at sections 1 and 2 respectively.
p1 and p2 are the pressures at sections 1 and 2 respectively.
z1 and z2 are the elevations of sections 1 and 2 respectively.
hf is the head loss due to friction.
g is the acceleration due to gravity.

As the water level in the tank is constant, the pressure at section 1 and 2 will be atmospheric pressure. Therefore,
p1 = p2 = atmospheric pressure

Also, the head loss due to friction can be neglected as the orifices are small.

Thus, the Bernoulli's equation reduces to:

v1^2/2g + z1 = v2^2/2g + z2

As the discharge through both the orifices is the same, we have:

v1A1 = v2A2

Where,
A1 = cross-sectional area of the first orifice = πd1^2/4
A2 = cross-sectional area of the second orifice = πd2^2/4

Substituting the values of A1 and A2 in the above equation, we get:

v1d1^2 = v2d2^2

Substituting this in the Bernoulli's equation, we get:

d1^2/d2^2 = h2/h1

Substituting the given values, we get:

d1^2/d2^2 = 4

Taking the square root of both sides, we get:

d1/d2 = 2

Therefore, the ratio of the diameters d1 and d2 will be 2:1. Hence, option (C) is the correct answer.
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Community Answer
Two small circular ofifices of diameters d1 and d2 are placed on one s...
Since discharge remains constant.

Q1 = Q2,
A1 v1 = A2 V2,
Substitute the equation.
A1/A2 = (√h2/√h1).
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Two small circular ofifices of diameters d1 and d2 are placed on one side of a tank at depths of 25 cm and 1 m respectively below a constantsurface of water. If the discharges through theorifice are the same, then the ratio of the diameters d1 and d2 will bea)1 :2b)1: √2c)√2 :1d)2 : 1Correct answer is option 'C'. Can you explain this answer?
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