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Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.
CN- : Both carbon and nitrogen are donor.
OCN- : Both oxygen and nitrogen are donor etc.
In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.
Q. 
When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product because
  • a)
    negative charge on nitrogen in NaNCO and on oxygen in AgNCO
  • b)
    negative charge on oxygen atom in both salts
  • c)
    free NCO- in case of NaNCO and covalent Ag —N bond in AgNCO
  • d)
    greater basicity of nitrogen In NaNCO and oxygen in AgNCO
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Nucleophiles which have more than one type of donor atoms within the s...
With free NCO-, better donor atom (nitrogen) donate its lone pair. If AgNCO is used, due to covalent character of Ag—N bond lone pair of oxygen is donated giving CH3CH2— OCN as major product.
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Most Upvoted Answer
Nucleophiles which have more than one type of donor atoms within the s...

Explanation:

Reason for the major product formation:
- When iodomethane reacts with sodium isocyanate (NaNCO) or silver isocyanate (AgNCO), the major product formed is CH3NCO and CH3CH2OCN respectively.
- This difference in product formation is due to the nature of the isocyanate ion (NCO-).

Explanation of option 'C':
- The major reason for the different products formed is the difference in the nature of the NCO- ion in NaNCO and AgNCO.
- In the case of NaNCO, the NCO- ion is free and has a negative charge on the nitrogen atom, making it a free anionic nucleophile.
- In the case of AgNCO, the NCO- ion forms a covalent bond with silver, which changes the nature of the nucleophile to an ambident nucleophile.
- The free NCO- ion in NaNCO has a greater tendency to donate its lone pair of electrons to the electrophile, resulting in the formation of CH3NCO as the major product.
- On the other hand, the NCO- ion in AgNCO has a covalent N bond with silver, which affects its donor ability and results in the formation of CH3CH2OCN as the major product.

Therefore, the correct explanation for the major product formation in the reaction of iodomethane with NaNCO and AgNCO lies in the difference in the nature of the NCO- ion in the two salts.
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Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer?
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Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Nucleophiles which have more than one type of donor atoms within the same donor group are known as ambident nucleophile e.g.CN-: Both carbon and nitrogen are donor.OCN-: Both oxygen and nitrogen are donor etc.In case of free anionic and ambident nucleophiles, the better donor atom donate its lone pair of electron and forms bond with a-carbon after substitution reaction, in a given period, donor ability decreases from left to right. In a group, donor ability increases from top to bottom.Q.When iodomethane is treated with sodium isocyanate (NaNCO), CH3NCO is the major product while AgNCO gives CH3CH2OCN as major product becausea)negative charge on nitrogen in NaNCO and on oxygen in AgNCOb)negative charge on oxygen atom in both saltsc)free NCO-in case of NaNCO and covalent Ag —N bond in AgNCOd)greater basicity of nitrogen In NaNCO and oxygen in AgNCOCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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