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A force of 20 newton acting on a body of mass 10 kg is found to double its velocity in 8 second .find its initial velocity?
Verified Answer
A force of 20 newton acting on a body of mass 10 kg is found to double...
Let the initial velocity be u
final velocity,v=2u
f=20  ,  m=10kg   ,  t=8 sec
f=ma
a=f/m
  =20/10
  =2m/s^2
v=u+at
2u=u+2*8
2u-u=16
u=16 m/s
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Most Upvoted Answer
A force of 20 newton acting on a body of mass 10 kg is found to double...
Given:
- Force (F) = 20 N
- Mass (m) = 10 kg
- Change in velocity (Δv) = 2v (double the initial velocity)
- Time (t) = 8 s

To find:
- Initial velocity (u)

Formula:
The relationship between force, mass, and acceleration is given by Newton's second law of motion:
F = ma

Acceleration (a) can also be expressed in terms of change in velocity and time:
a = Δv / t

Using these formulas, we can derive the equation to find the initial velocity:
F = ma
20 N = 10 kg * a
a = 2 m/s²

Solution:

Step 1: Find the acceleration
Given that the change in velocity (Δv) is double the initial velocity (2v), we can calculate the acceleration using the formula:
a = Δv / t
a = (2v - u) / t
2 = (2v - u) / 8
16 = 2v - u
u = 2v - 16

Step 2: Substitute the known values
We know that the force acting on the body is 20 N and the mass of the body is 10 kg. Using Newton's second law of motion, we can find the acceleration:
F = ma
20 N = 10 kg * a
a = 2 m/s²

Step 3: Solve for the initial velocity
Substituting the value of acceleration (a) into the equation from Step 1:
u = 2v - 16
2 = 2v - 16
2v = 18
v = 9 m/s

Thus, the initial velocity of the body is 9 m/s.
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A force of 20 newton acting on a body of mass 10 kg is found to double its velocity in 8 second .find its initial velocity?
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