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A force of 0.6N acting on a body increases its velocity from 5 meters per second to 6 meters per second in 2 second. Calculate the mass of the body.?
Most Upvoted Answer
A force of 0.6N acting on a body increases its velocity from 5 meters ...
Given:
Force (F) = 0.6 N
Initial velocity (u) = 5 m/s
Final velocity (v) = 6 m/s
Time (t) = 2 s
Formula:
The relationship between force, mass, and acceleration is given by Newton's second law of motion:
F = m * a
Where F is the force applied, m is the mass of the body, and a is the acceleration produced.
The formula to calculate acceleration is:
a = (v - u) / t
Where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time taken.
Calculation:
Substituting the given values into the formula:
a = (6 - 5) / 2
a = 1 / 2
a = 0.5 m/s²
Now, we can use Newton's second law of motion to calculate the mass:
F = m * a
0.6 = m * 0.5
Solving for m:
m = 0.6 / 0.5
m = 1.2 kg
Answer:
The mass of the body is 1.2 kg.
Force (F) = 0.6 N
Initial velocity (u) = 5 m/s
Final velocity (v) = 6 m/s
Time (t) = 2 s
Formula:
The relationship between force, mass, and acceleration is given by Newton's second law of motion:
F = m * a
Where F is the force applied, m is the mass of the body, and a is the acceleration produced.
The formula to calculate acceleration is:
a = (v - u) / t
Where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time taken.
Calculation:
Substituting the given values into the formula:
a = (6 - 5) / 2
a = 1 / 2
a = 0.5 m/s²
Now, we can use Newton's second law of motion to calculate the mass:
F = m * a
0.6 = m * 0.5
Solving for m:
m = 0.6 / 0.5
m = 1.2 kg
Answer:
The mass of the body is 1.2 kg.
Community Answer
A force of 0.6N acting on a body increases its velocity from 5 meters ...
Acceleration=(v-u)/t
=(6-5m/s)/2s
=1/2m/s^2
=0.5m/s^2
F=0.6N
F=ma(from Newton's 2nd law of motion)
0.6N=m×0.5m/s^2
m=0.6/0.5
m=1.2kg
UPvote and lemme know if that helped:)
=(6-5m/s)/2s
=1/2m/s^2
=0.5m/s^2
F=0.6N
F=ma(from Newton's 2nd law of motion)
0.6N=m×0.5m/s^2
m=0.6/0.5
m=1.2kg
UPvote and lemme know if that helped:)
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A force of 0.6N acting on a body increases its velocity from 5 meters per second to 6 meters per second in 2 second. Calculate the mass of the body.?
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A force of 0.6N acting on a body increases its velocity from 5 meters per second to 6 meters per second in 2 second. Calculate the mass of the body.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A force of 0.6N acting on a body increases its velocity from 5 meters per second to 6 meters per second in 2 second. Calculate the mass of the body.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force of 0.6N acting on a body increases its velocity from 5 meters per second to 6 meters per second in 2 second. Calculate the mass of the body.?.
A force of 0.6N acting on a body increases its velocity from 5 meters per second to 6 meters per second in 2 second. Calculate the mass of the body.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A force of 0.6N acting on a body increases its velocity from 5 meters per second to 6 meters per second in 2 second. Calculate the mass of the body.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force of 0.6N acting on a body increases its velocity from 5 meters per second to 6 meters per second in 2 second. Calculate the mass of the body.?.
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