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4. The gradient of xi + yj + zk is
- a)0
- b)1
- c)2
- d)3
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option...
Answer: d
Explanation: Grad (xi + yj + zk) = 1 + 1 + 1 = 3. In other words, the gradient of any position vector is 3.
Explanation: Grad (xi + yj + zk) = 1 + 1 + 1 = 3. In other words, the gradient of any position vector is 3.
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4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option...
The gradient of a vector function measures the rate of change of the function with respect to each of its variables. In this case, we are given a vector function of the form xi + yj + zk, where x, y, and z are variables.
The gradient of a vector function is a vector that consists of the partial derivatives of the function with respect to each variable. In this case, we need to calculate the partial derivatives of xi, yj, and zk with respect to x, y, and z, respectively.
The partial derivative of xi with respect to x is 1, because the derivative of x with respect to x is 1 and the derivative of any constant (in this case, i) with respect to any variable is 0. Similarly, the partial derivatives of yj and zk with respect to y and z are 1.
Therefore, the gradient of xi + yj + zk is given by the vector (1, 1, 1). This means that the rate of change of the function with respect to each variable is 1. In other words, for a small change in x, y, or z, the function increases by 1 unit.
So, the correct answer is option 'D' - 3.
The gradient of a vector function is a vector that consists of the partial derivatives of the function with respect to each variable. In this case, we need to calculate the partial derivatives of xi, yj, and zk with respect to x, y, and z, respectively.
The partial derivative of xi with respect to x is 1, because the derivative of x with respect to x is 1 and the derivative of any constant (in this case, i) with respect to any variable is 0. Similarly, the partial derivatives of yj and zk with respect to y and z are 1.
Therefore, the gradient of xi + yj + zk is given by the vector (1, 1, 1). This means that the rate of change of the function with respect to each variable is 1. In other words, for a small change in x, y, or z, the function increases by 1 unit.
So, the correct answer is option 'D' - 3.
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4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option...
|xi+yj+zk|=|i^2+j^2+k^2|=1+1+1=3
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4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about 4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option 'D'. Can you explain this answer?.
4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about 4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 4. The gradient of xi + yj + zk isa)0b)1c)2d)3Correct answer is option 'D'. Can you explain this answer?.
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