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A bar of circular cross section is clamped at ends P and Q as shown in the figure. A torsional moment T = 150 Nm is applied at a distance of 100 mm from end P. The torsional reactions (TP,TQ) in Nm at the ends P and Q respectively are
  • a)
    (50,100)
  • b)
    (75,75)
  • c)
    (100,50)
  • d)
    (120,30)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A bar of circular cross section is clamped at ends P and Q as shown in...
Since, G and are constant for bar,
T1L1=T2L2
T1.100=T2.200
T1=2T2
And, T1 + T2 = T
Hence, T1 = 100nm T2 = 50Nm
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A bar of circular cross section is clamped at ends P and Q as shown in the figure. A torsional moment T = 150 Nm is applied at a distance of 100 mm from end P. The torsional reactions (TP,TQ)in Nm at the ends P and Q respectively area)(50,100)b)(75,75)c)(100,50)d)(120,30)Correct answer is option 'C'. Can you explain this answer?
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A bar of circular cross section is clamped at ends P and Q as shown in the figure. A torsional moment T = 150 Nm is applied at a distance of 100 mm from end P. The torsional reactions (TP,TQ)in Nm at the ends P and Q respectively area)(50,100)b)(75,75)c)(100,50)d)(120,30)Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A bar of circular cross section is clamped at ends P and Q as shown in the figure. A torsional moment T = 150 Nm is applied at a distance of 100 mm from end P. The torsional reactions (TP,TQ)in Nm at the ends P and Q respectively area)(50,100)b)(75,75)c)(100,50)d)(120,30)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar of circular cross section is clamped at ends P and Q as shown in the figure. A torsional moment T = 150 Nm is applied at a distance of 100 mm from end P. The torsional reactions (TP,TQ)in Nm at the ends P and Q respectively area)(50,100)b)(75,75)c)(100,50)d)(120,30)Correct answer is option 'C'. Can you explain this answer?.
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