In how much time (in years) will Rs. 8000 amount to Rs. 9600 at simple...
Simple interest = (P × t × r)/100
P = Principal
t = Time period
r = Rate of interest
Given,
P = Rs. 8000
r = 5%
Simple Interest = Rs. (9600 - 8000) = Rs. 1600
1600 = (8000 × t × 5)/100
⇒ 400 t = 1600
⇒ t = 4 years
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In how much time (in years) will Rs. 8000 amount to Rs. 9600 at simple...
Given:
Principal amount (P) = Rs. 8000
Amount (A) = Rs. 40,000
Rate of interest (R) = 4%
Time (T) =?
Formula Used:
Simple Interest = (P * R * T)/100
Amount = P + Simple Interest
Explanation:
We have to find the time required for Rs. 8000 to grow to Rs. 40,000 at a rate of 4% per annum.
Let's assume the time required is T years.
Using the formula of simple interest, we can calculate the interest earned in T years as follows:
Simple Interest = (P * R * T)/100 = (8000 * 4 * T)/100 = 320T
Now, we can calculate the amount after T years as follows:
Amount = P + Simple Interest = 8000 + 320T
We know that the final amount is Rs. 40,000. So we can equate the above equation to 40,000 and solve for T as follows:
8000 + 320T = 40,000
320T = 32,000
T = 100 years
Therefore, it will take 100 years for Rs. 8000 to grow to Rs. 40,000 at a rate of 4% per annum, when simple interest is being used.
Answer: Option A (100 years)