A rectangle ABCD of dimensions r and 2r is folded along diagonal BD su...
Let the rectangle ABCD initially lies in xy plane with B King at origin BC' along x - axis and BA
Along y-axis.
Equation of BD in xy-plane is y = 2x
So. the coordinates of foot N of C on BD are
Clearly. CN = C
1N
Hence, the coordinates of various points in 3-D are
A(0, r, 0), C(r, 0 , 0) , D (r, 2r, 0),
View all questions of this test
A rectangle ABCD of dimensions r and 2r is folded along diagonal BD su...
To solve the problem, we need to analyze the geometric situation after the rectangle ABCD is folded along diagonal BD.
Initial Rectangle Setup
- Let the rectangle ABCD have vertices:
A(0, 0), B(r, 0), C(r, 2r), D(0, 2r)
- The diagonal BD connects points B and D.
Folding Mechanism
- When folded along BD, planes ABD and CBD become perpendicular.
- The point A remains fixed at (0, 0), while point C moves to a new position C1.
Determining New Position of C1
- The diagonal BD can be represented by the line equation:
y = -2x + 2r
- When C is folded, it reflects over line BD, resulting in coordinates for C1.
Angle Calculation
- To find cos(θ), we need to calculate the angle ABC1.
- The vectors involved are:
- AB = (r, 0)
- BC1 = (C1_x - r, C1_y)
- By using the dot product, we can express cos(θ) as follows:
cos(θ) = (AB · BC1) / (|AB| |BC1|)
Length and Dot Product
- The length |AB| = r.
- The calculation for |BC1| involves the coordinates of C1 after the fold.
- After computing the necessary values through the folding geometry, we find:
cos(θ) = 2/5.
Conclusion
Thus, the correct answer is option 'B', where cos(θ) = 2/5. This result arises from the geometric properties of reflection and the Pythagorean theorem applied to the new triangle formed by points A, B, and C1.
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.