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The value of integral

over the closed surface S bounding a volume, whereis the position vector
and  is the normal to the surface S, is
  • a)
    V
  • b)
    2 V
  • c)
    3 V
  • d)
    4 V
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The value of integralover the closed surface S bounding a volume, wher...
By Gauss Divergence Theorem

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The value of integralover the closed surface S bounding a volume, whereis the position vectorand is the normal to the surface S, isa)Vb)2 Vc)3 Vd)4 VCorrect answer is option 'C'. Can you explain this answer?
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