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A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer?.
Solutions for A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer?, a detailed solution for A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer? has been provided alongside types of A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A right angle triangle ABC, right angle at A is inscribed in hyperbola xy = c2(c > 0) such that slope of BC is 2. If distance of point A from centre of xy = c2is√10, then which of the following is/are correct for xy = c2a)the value of c is 2b)the value of c is 4c)the equation of normal at point A can bey = 2x − 3√2d)the equation of normal at point A can bey = 3x + 8√2Correct answer is option 'A,C'. Can you explain this answer? tests, examples and also practice JEE tests.