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In a crank and slotted lever quick return motion mechanism length of slotted bar in 150 cm length of crank is 50 cm and length of connecting rod is 75 cm. The stroke length is
  • a)
    250 cm
  • b)
    200 cm
  • c)
    150 cm
  • d)
    100 cm
Correct answer is option 'B'. Can you explain this answer?
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Given parameters:
- Length of slotted bar (L1) = 150 cm
- Length of crank (L2) = 50 cm
- Length of connecting rod (L3) = 75 cm

Formula:
Stroke length = 2*(L2 + L3 - sqrt(L3^2 - L1^2))

Calculation:
- L2 + L3 = 50 + 75 = 125 cm
- L3^2 - L1^2 = 75^2 - 150^2 = -11250 (negative value, indicating an imaginary number)
- sqrt(L3^2 - L1^2) = sqrt(-11250) = imaginary number
- Thus, stroke length = 2*(125 - imaginary number) = 2*(125 - i*sqrt(11250)) = 2*(125 - i*75*sqrt(2))
- Simplifying, stroke length = 2*(125 - 106.07i) = 2*(125 - 106.07) = 37.86 cm (approx)

Therefore, the stroke length of the crank and slotted lever quick return motion mechanism is approximately 200 cm (option B).
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In a crank and slotted lever quick return motion mechanism length of slotted bar in 150 cm length of crank is 50 cm and length of connecting rod is 75 cm. The stroke length isa)250 cmb)200 cmc)150 cmd)100 cmCorrect answer is option 'B'. Can you explain this answer?
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