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In the above question, find the probability that the remaining two balls are red.
- a)10/231
- b)12/231
- c)12/363
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
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In the above question, find the probability that the remaining two bal...
The required probability would be given by the event definition: First is red and second is red = 5/22 x 4/21 = 10/231
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In the above question, find the probability that the remaining two bal...
To find the probability that a number selected at random from the first 50 natural numbers is a multiple of both 3 and 4, we need to determine the number of numbers that are multiples of both 3 and 4 and then divide it by the total number of numbers.
Finding the numbers that are multiples of 3:
The multiples of 3 within the first 50 natural numbers are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, and 48. There are 16 numbers that are multiples of 3.
Finding the numbers that are multiples of 4:
The multiples of 4 within the first 50 natural numbers are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, and 48. There are 12 numbers that are multiples of 4.
Finding the numbers that are multiples of both 3 and 4:
The numbers that are multiples of both 3 and 4 are the numbers that are multiples of their least common multiple, which is 12. The multiples of 12 within the first 50 natural numbers are 12, 24, 36, and 48. There are 4 numbers that are multiples of both 3 and 4.
Calculating the probability:
The total number of numbers within the first 50 natural numbers is 50.
Therefore, the probability that a number selected at random from the first 50 natural numbers is a multiple of both 3 and 4 is given by:
Probability = (Number of numbers that are multiples of both 3 and 4) / (Total number of numbers)
Probability = 4 / 50
Simplifying the fraction, we get:
Probability = 2 / 25
Hence, the correct answer is option A) 2/25.
Finding the numbers that are multiples of 3:
The multiples of 3 within the first 50 natural numbers are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, and 48. There are 16 numbers that are multiples of 3.
Finding the numbers that are multiples of 4:
The multiples of 4 within the first 50 natural numbers are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, and 48. There are 12 numbers that are multiples of 4.
Finding the numbers that are multiples of both 3 and 4:
The numbers that are multiples of both 3 and 4 are the numbers that are multiples of their least common multiple, which is 12. The multiples of 12 within the first 50 natural numbers are 12, 24, 36, and 48. There are 4 numbers that are multiples of both 3 and 4.
Calculating the probability:
The total number of numbers within the first 50 natural numbers is 50.
Therefore, the probability that a number selected at random from the first 50 natural numbers is a multiple of both 3 and 4 is given by:
Probability = (Number of numbers that are multiples of both 3 and 4) / (Total number of numbers)
Probability = 4 / 50
Simplifying the fraction, we get:
Probability = 2 / 25
Hence, the correct answer is option A) 2/25.
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In the above question, find the probability that the remaining two balls are red.a)10/231b)12/231c)12/363d)None of theseCorrect answer is option 'A'. Can you explain this answer?
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