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A pure inductor of 25mH is connected to a source of 220V 50Hz.find the inductive reactance, Irms and peak value of the circuit.?
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A pure inductor of 25mH is connected to a source of 220V 50Hz.find the...
Introduction

In this scenario, we have a pure inductor with an inductance of 25mH connected to a source of 220V and a frequency of 50Hz. We need to find the inductive reactance, Irms, and peak value of the circuit.

Inductive Reactance (XL)

Inductive reactance is a property of an inductor that opposes changes in current. It is given by the formula XL = 2πfL, where XL is the inductive reactance, f is the frequency, and L is the inductance.

Given:
- Inductance (L) = 25mH = 25 * 10^-3 H
- Frequency (f) = 50Hz

Using the formula, XL = 2πfL, we can calculate the inductive reactance.

XL = 2π * 50 * (25 * 10^-3)
= 2π * 50 * 0.025
= 3.14 * 50 * 0.025
= 3.14 * 1.25
= 3.925Ω

Therefore, the inductive reactance of the circuit is 3.925Ω.

Irms (Root Mean Square Current)

Irms is the effective or average value of the current flowing through the circuit over one complete cycle. It can be calculated using the formula Irms = Vrms / XL, where Vrms is the root mean square voltage and XL is the inductive reactance.

Given:
- Voltage (V) = 220V

To find the root mean square voltage (Vrms), we need to know the type of waveform. Assuming it is a sinusoidal waveform, the formula to find Vrms from the peak voltage (Vpeak) is Vrms = Vpeak / √2.

Given:
- Voltage (V) = 220V

Using the formula, Vrms = V / √2, we can calculate the root mean square voltage.

Vrms = 220 / √2
= 220 / 1.414
= 155.56V

Now, we can calculate the Irms using the formula Irms = Vrms / XL.

Irms = 155.56 / 3.925
= 39.64A

Therefore, the root mean square current (Irms) flowing through the circuit is 39.64A.

Peak Value

The peak value of the current is the maximum value attained by the current during one complete cycle. It can be calculated using the formula Ipeak = √2 * Irms.

Given:
- Irms = 39.64A

Using the formula, Ipeak = √2 * Irms, we can calculate the peak value of the current.

Ipeak = √2 * 39.64
= 55.97A

Therefore, the peak value of the current in the circuit is 55.97A.

Conclusion

In conclusion, the inductive reactance of the circuit is 3.925Ω. The root mean square current (Irms) flowing through the circuit is 39.64A, and the peak value of the current is 55.97A. These values are calculated
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Read the following text and answer the following questions on the basis of the same: Power factor correction capacitor Power factor correction is a method to reduce the lagging power factor in inductive loads by fixing a high value capacitor across the phase and neutral line close to the load. When the Voltage and Current are in phase with each other in an AC circuit, the energy from the source is fully converted into another form to drive the load and in this case the power factor is in unity. When the power factor drops, the system becomes less efficient. In inductive loads, current “lags'' the voltage leading to “lagging power factor”. Power factor correction is the method to reduce the lagging power factor in inductive loads by fixing a high value capacitor across the phase and neutral close to the load. These capacitors have leading power factor so that it will neutralize the lagging power factor of the load. Power capacitors are huge non polarized metal film electrolytic type capacitors. Capacitors should be sufficiently rated to the load capacity. It should be connected to the lines, only when the loads are running and drawing currentPower factor corrector capacitors should be connected

Read the following text and answer the following questions on the basis of the same:Power factor correction capacitor Power factor correction is a method to reduce the lagging power factor in inductive loads by fixing a high value capacitor across the phase and neutral line close to the load. When the Voltage and Current are in phase with each other in an AC circuit, the energy from the source is fully converted into another form to drive the load and in this case the power factor is in unity. When the power factor drops, the system becomes less efficient. In inductive loads, current “lags'' the voltage leading to “lagging power factor”. Power factor correction is the method to reduce the lagging power factor in inductive loads by fixing a high value capacitor across the phase and neutral close to the load. These capacitors have a leading power factor so that it will neutralize the lagging power factor of the load. Power capacitors are huge non polarized metal film electrolytic type capacitors. Capacitors should be sufficiently rated to the load capacity. It should be connected to the lines, only when the loads are running and drawing currentWhen the energy from source is fully converted into another form, the power factor is

A pure inductor of 25mH is connected to a source of 220V 50Hz.find the inductive reactance, Irms and peak value of the circuit.?
Question Description
A pure inductor of 25mH is connected to a source of 220V 50Hz.find the inductive reactance, Irms and peak value of the circuit.? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A pure inductor of 25mH is connected to a source of 220V 50Hz.find the inductive reactance, Irms and peak value of the circuit.? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pure inductor of 25mH is connected to a source of 220V 50Hz.find the inductive reactance, Irms and peak value of the circuit.?.
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