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The displacement of a particle is given x=6Cos omega t+8 sin omega t. This equation represents simple harmonic oscillation having amplitude: a) 14m b)2m c) 10m d)5m?
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The displacement of a particle is given x=6Cos omega t+8 sin omega t. ...
Amplitude of Simple Harmonic Oscillation
The equation for the displacement of a particle is given as x = 6Cos(ωt) + 8Sin(ωt).

Finding the Amplitude
To find the amplitude of the simple harmonic oscillation represented by this equation, we can rewrite it in the form of ACos(ωt - φ), where A is the amplitude.
Given x = 6Cos(ωt) + 8Sin(ωt), we can rewrite it as:
x = √(6^2 + 8^2)Cos(ωt + φ), where φ is the phase angle.

Calculating the Amplitude
The amplitude A can be calculated as:
A = √(6^2 + 8^2) = √(36 + 64) = √100 = 10
Therefore, the amplitude of the simple harmonic oscillation represented by the given equation is 10m.

Conclusion
The correct option is:
c) 10m
By following the steps mentioned above, we can determine the amplitude of a simple harmonic oscillation represented by a given equation.
Community Answer
The displacement of a particle is given x=6Cos omega t+8 sin omega t. ...
10m
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