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Consider the reaction 2NO(g)+O2(g) ⟶ 2NO2(g) Predict whether the reaction is spontaneous at 298 K. ΔfG(NO) = 86.69kJ/mol,ΔfG(NO2) = 51.84kJ/mol
- a)Yes, Spontaneous
- b)No, the reaction is Non-spontaneous
- c)Equilibrium
- d)Can not predict
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Consider the reaction 2NO(g)+O2(g) ⟶ 2NO2(g) Predict whether th...
2NO(g)+O2(g) ⟶ 2NO2(g)
ΔG = 2ΔfG(NO2)−[2ΔfG(NO)+ΔfG(O2)]
= (2×51.84)−(2×86.69+0)
= 103.68−173.38
= −69.7kJ/mol ; Δ G is negative
So the reaction is spontaneous
ΔG = 2ΔfG(NO2)−[2ΔfG(NO)+ΔfG(O2)]
= (2×51.84)−(2×86.69+0)
= 103.68−173.38
= −69.7kJ/mol ; Δ G is negative
So the reaction is spontaneous
Most Upvoted Answer
Consider the reaction 2NO(g)+O2(g) ⟶ 2NO2(g) Predict whether th...
Given Data:
- ΔfG(NO) = 86.69 kJ/mol
- ΔfG(NO2) = 51.84 kJ/mol
Calculation:
- ΔfG = ΣΔfG(products) - ΣΔfG(reactants)
- ΔfG(NO2) = 2(51.84) = 103.68 kJ/mol
- ΔfG(NO) = 2(86.69) = 173.38 kJ/mol
- ΔfG = 103.68 - 173.38 = -69.7 kJ/mol
Analysis:
Since the ΔfG value is negative (-69.7 kJ/mol), the reaction is spontaneous at 298 K. The negative value indicates that the products have lower free energy compared to the reactants, driving the reaction forward without the need for external energy input.
Therefore, the correct answer is Yes, Spontaneous.
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Consider the reaction 2NO(g)+O2(g) ⟶ 2NO2(g) Predict whether the reaction is spontaneous at 298 K. ΔfG(NO) = 86.69kJ/mol,ΔfG(NO2) = 51.84kJ/mola)Yes, Spontaneousb)No, the reaction is Non-spontaneousc)Equilibriumd)Can not predictCorrect answer is option 'A'. Can you explain this answer?
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