To find the area bounded by the given curves, we need to determine the points of intersection between the two curves and then calculate the area enclosed between them. Let's solve the equations step by step.

1. Finding the points of intersection:
We have two equations: y^2 = 9x and x - y^2 = 0.
By substituting the value of y^2 from the second equation into the first equation, we get:
9x = x^2
Rearranging the equation, we have:
x^2 - 9x = 0
Factoring out x, we get:
x(x - 9) = 0
So, we have two possible solutions for x:
x = 0 and x = 9

Substituting these values back into the second equation, we can find the corresponding y-values:
For x = 0, y = 0 (from x - y^2 = 0)
For x = 9, y = ±3 (from x - y^2 = 0)

Therefore, the points of intersection are: (0, 0) and (9, 3) or (9, -3).

2. Calculating the area:
To find the area enclosed between the curves, we need to integrate the difference between the curves with respect to x over the interval [0, 9].

The curves are y^2 = 9x and x - y^2 = 0.
Rearranging the first equation, we get:
y^2 - 9x = 0
Solving for y, we have:
y = ±√(9x)

Now we can set up the integral:
Area = ∫[0, 9] (√(9x) - √(x)) dx

Simplifying the integral and evaluating it, we get:
Area = [2/3 * (9x)^(3/2) - 2/3 * x^(3/2)]|[0, 9]
Area = [(2/3 * (9^2)^(3/2) - 2/3 * 9^(3/2)) - (2/3 * (0)^(3/2) - 2/3 * (0)^(3/2))]
Area = [(2/3 * 81^(3/2) - 2/3 * 9^(3/2)) - (0 - 0)]
Area = [(2/3 * 81 * √(81) - 2/3 * 9 * √(9)) - 0]
Area = [(2/3 * 81 * 9 - 2/3 * 9 * 3) - 0]
Area = [(2/3 * 729 - 2/3 * 27) - 0]
Area = [(486 - 18) - 0]
Area = 468

Therefore, the area bounded by the curves y^2 = 9x and x - y^2 = 0 is 468 square units.

The correct answer is option B) 1/2.