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A refrigeration system operates on the reversed Carnot cycle. The temperature for the system is: Higher temperature = 40°C and Lower temperature = 20°C.
The capacity of the refrigeration system is 10 TR. What is the heat rejected from the system per hour if all the losses are neglected? 
  • a)
    1·25 kJ/hr  
  • b)
    1·55 kJ/hr  
  • c)
    2·3 kJ/hr
  • d)
    None of the above  
Correct answer is option 'D'. Can you explain this answer?
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Refrigeration System Operating on Reversed Carnot Cycle

Higher temperature (Th) = 40°C
Lower temperature (Tl) = 20°C
Capacity of the refrigeration system = 10 TR

Calculation of Heat Rejected from the System per Hour

The efficiency of the reversed Carnot cycle is given by:
η = (Th - Tl)/Th

The COP (Coefficient of Performance) of the refrigeration system is given by:
COP = Th/(Th - Tl)

The heat absorbed by the refrigeration system per hour is given by:
Qh = COP x Capacity

Substituting the values, we get:
Qh = 40/(40 - 20) x 10 TR
Qh = 20 x 10 TR
Qh = 200 TR

The heat rejected by the refrigeration system per hour is given by:
Ql = Qh - Capacity

Substituting the values, we get:
Ql = 200 TR - 10 TR
Ql = 190 TR

Converting TR to kJ/hr, we get:
1 TR = 3.5169 kW
Therefore, 190 TR = 668.613 kW

Thus, the heat rejected from the system per hour is 668.613 kJ/hr. Therefore, option D is the correct answer.
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