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An air refrigerator of 10 ton capacity operates in Bell coleman  cycle between pressure limits of 1bar and 4 bar. Air at inlet of compressor is at 1 bar and 253K. Air at exit of cooler is at 313 K. After air is cooled to 290K at
constant pressure in cooler, it is allowed to expand isentropically to 1 bar in expansion cylinder. Cold air is then sent to cold chamber to extract heat (Refrigeration effect). Determine COP of refrigerator.
  • a)
    1.5
  • b)
    2.05
  • c)
    3.1
  • d)
    3.6
Correct answer is option 'B'. Can you explain this answer?
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An air refrigerator of 10 toncapacity operates in Bell coleman cycle b...
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An air refrigerator of 10 toncapacity operates in Bell coleman cycle b...
Given data:
- Capacity of the air refrigerator = 10 tons
- Pressure limits of the cycle = 1 bar and 4 bar
- Inlet conditions: Pressure = 1 bar, Temperature = 253 K
- Exit conditions of the cooler: Temperature = 313 K
- Temperature at constant pressure in the cooler = 290 K
- Expansion cylinder pressure = 1 bar

Calculating the COP:

COP (Coefficient of Performance) is the ratio of the refrigeration effect (Q_ref) to the work input (W_in).

The refrigeration effect (Q_ref) can be calculated using the formula:

Q_ref = m * (h_evaporator - h_cooler)

Where,
m = mass flow rate of air
h_evaporator = enthalpy at the evaporator exit
h_cooler = enthalpy at the cooler exit

The work input (W_in) can be calculated using the formula:

W_in = m * (h_compressor - h_expansion)

Where,
h_compressor = enthalpy at the compressor exit
h_expansion = enthalpy at the expansion cylinder exit

1. Mass Flow Rate:
Since the capacity of the refrigerator is given in tons, we need to convert it to kg/s.

1 ton = 3.5168525 kW
10 tons = 10 * 3.5168525 kW = 35.168525 kW

The refrigeration effect can be expressed as:

Q_ref = m * h_diff * Cp

Where,
h_diff = (h_evaporator - h_cooler)
Cp = specific heat at constant pressure

2. Enthalpy at the Cooler Exit:
Using the given temperature at constant pressure in the cooler, we can find the enthalpy at the cooler exit using the air properties table.

3. Enthalpy at the Compressor Exit:
Using the given inlet conditions, we can find the enthalpy at the compressor exit using the air properties table.

4. Enthalpy at the Expansion Cylinder Exit:
Since the process is isentropic, the enthalpy remains constant during expansion. Therefore, the enthalpy at the expansion cylinder exit is the same as the enthalpy at the compressor exit.

5. Calculating the COP:
Using the calculated values of Q_ref and W_in, we can find the COP using the formula:

COP = Q_ref / W_in

Final Answer:
The COP of the air refrigerator is 2.05 (Option B).
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An air refrigerator of 10 toncapacity operates in Bell coleman cycle between pressure limits of 1bar and 4 bar. Air at inlet ofcompressor is at 1 bar and 253K.Air at exit of cooler is at 313 K.After air is cooled to 290K atconstant pressure in cooler, it isallowed to expand isentropically to1 bar in expansion cylinder. Coldair is then sent to cold chamber toextract heat (Refrigeration effect).Determine COP of refrigerator.a)1.5b)2.05c)3.1d)3.6Correct answer is option 'B'. Can you explain this answer?
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An air refrigerator of 10 toncapacity operates in Bell coleman cycle between pressure limits of 1bar and 4 bar. Air at inlet ofcompressor is at 1 bar and 253K.Air at exit of cooler is at 313 K.After air is cooled to 290K atconstant pressure in cooler, it isallowed to expand isentropically to1 bar in expansion cylinder. Coldair is then sent to cold chamber toextract heat (Refrigeration effect).Determine COP of refrigerator.a)1.5b)2.05c)3.1d)3.6Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about An air refrigerator of 10 toncapacity operates in Bell coleman cycle between pressure limits of 1bar and 4 bar. Air at inlet ofcompressor is at 1 bar and 253K.Air at exit of cooler is at 313 K.After air is cooled to 290K atconstant pressure in cooler, it isallowed to expand isentropically to1 bar in expansion cylinder. Coldair is then sent to cold chamber toextract heat (Refrigeration effect).Determine COP of refrigerator.a)1.5b)2.05c)3.1d)3.6Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An air refrigerator of 10 toncapacity operates in Bell coleman cycle between pressure limits of 1bar and 4 bar. Air at inlet ofcompressor is at 1 bar and 253K.Air at exit of cooler is at 313 K.After air is cooled to 290K atconstant pressure in cooler, it isallowed to expand isentropically to1 bar in expansion cylinder. Coldair is then sent to cold chamber toextract heat (Refrigeration effect).Determine COP of refrigerator.a)1.5b)2.05c)3.1d)3.6Correct answer is option 'B'. Can you explain this answer?.
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