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The mass of glucose that should be dissolved in 50 g of water in order to produce same lowering of vapor pressure as is produced by dissolving 1 g of Urea in same quantity of water?
Correct answer is '3'. Can you explain this answer?
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Explanation:
Colligative properties: Properties of a solution that depend on the number of solute particles in the solution but not on the nature of the solute particles. Vapor pressure lowering is one of the colligative properties of a solution.
Raoult's law: It states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent in the solution. Mathematically, Psolution = Xsolvent Psolvent, where Psolution is the vapor pressure of the solution, Xsolvent is the mole fraction of the solvent, and Psolvent is the vapor pressure of the pure solvent.
Vapor pressure lowering: It is given by the equation, ΔP = Psolvent - Psolution, where ΔP is the lowering of vapor pressure, Psolvent is the vapor pressure of the pure solvent, and Psolution is the vapor pressure of the solution.
Colligative property of vapor pressure lowering: If a nonvolatile solute is dissolved in a solvent, the vapor pressure of the solution will be lower than the vapor pressure of the pure solvent at the same temperature. The amount of lowering of vapor pressure depends on the mole fraction of the solute in the solution.
Calculation:
Given:
mass of Urea, m1 = 1 g
mass of water, m2 = 50 g
To find: mass of glucose, m3 that produces the same lowering of vapor pressure as produced by Urea.
From Raoult's law, we know that the mole fraction of Urea, X1 = m1/M1L2, where M1 is the molar mass of Urea and L2 is the solvent (water) volume in liters. Since the volume of water is not given, we assume it to be 50 mL (=0.05 L).
M1 = 60 g/mol (molar mass of Urea)
X1 = 1/60*0.05 = 0.0333
From the formula of vapor pressure lowering, we know that ΔP = Psolvent - Psolution = X1 Psolvent, where Psolvent is the vapor pressure of water at the given temperature.
For water at 25°C, Psolvent = 23.8 mmHg
ΔP = 0.0333*23.8 = 0.793 mmHg
Now
Colligative properties: Properties of a solution that depend on the number of solute particles in the solution but not on the nature of the solute particles. Vapor pressure lowering is one of the colligative properties of a solution.
Raoult's law: It states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent in the solution. Mathematically, Psolution = Xsolvent Psolvent, where Psolution is the vapor pressure of the solution, Xsolvent is the mole fraction of the solvent, and Psolvent is the vapor pressure of the pure solvent.
Vapor pressure lowering: It is given by the equation, ΔP = Psolvent - Psolution, where ΔP is the lowering of vapor pressure, Psolvent is the vapor pressure of the pure solvent, and Psolution is the vapor pressure of the solution.
Colligative property of vapor pressure lowering: If a nonvolatile solute is dissolved in a solvent, the vapor pressure of the solution will be lower than the vapor pressure of the pure solvent at the same temperature. The amount of lowering of vapor pressure depends on the mole fraction of the solute in the solution.
Calculation:
Given:
mass of Urea, m1 = 1 g
mass of water, m2 = 50 g
To find: mass of glucose, m3 that produces the same lowering of vapor pressure as produced by Urea.
From Raoult's law, we know that the mole fraction of Urea, X1 = m1/M1L2, where M1 is the molar mass of Urea and L2 is the solvent (water) volume in liters. Since the volume of water is not given, we assume it to be 50 mL (=0.05 L).
M1 = 60 g/mol (molar mass of Urea)
X1 = 1/60*0.05 = 0.0333
From the formula of vapor pressure lowering, we know that ΔP = Psolvent - Psolution = X1 Psolvent, where Psolvent is the vapor pressure of water at the given temperature.
For water at 25°C, Psolvent = 23.8 mmHg
ΔP = 0.0333*23.8 = 0.793 mmHg
Now
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The mass of glucose that should be dissolved in 50 g of water in order to produce same lowering of vapor pressure as is produced by dissolving 1 g of Urea in same quantity of water?Correct answer is '3'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The mass of glucose that should be dissolved in 50 g of water in order to produce same lowering of vapor pressure as is produced by dissolving 1 g of Urea in same quantity of water?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mass of glucose that should be dissolved in 50 g of water in order to produce same lowering of vapor pressure as is produced by dissolving 1 g of Urea in same quantity of water?Correct answer is '3'. Can you explain this answer?.
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