Molar concentration of H2SO4 in dilute solution:

To determine the molar concentration of H2SO4 in the dilute solution, we need to start by finding the number of moles of H2SO4 and the final volume of the solution.

1. Calculate the number of moles of Mg:
Given that 2.4 g of Mg is used, we can calculate the number of moles of Mg using its molar mass. The molar mass of Mg is 24.31 g/mol.

Number of moles of Mg = mass of Mg / molar mass of Mg
= 2.4 g / 24.31 g/mol
= 0.0988 mol

2. Determine the number of moles of H2SO4:
The balanced chemical equation between Mg and H2SO4 is:
Mg + H2SO4 → MgSO4 + H2

From the equation, we can see that the stoichiometric ratio between Mg and H2SO4 is 1:1. Therefore, the number of moles of H2SO4 is also 0.0988 mol.

3. Calculate the final volume of the solution:
The volume of the H2SO4 solution is given as 200 mL, but we need to convert it to liters for consistency with the molar concentration.

Final volume of the solution = 200 mL / 1000 mL/L
= 0.2 L

4. Calculate the molar concentration of H2SO4:
The molar concentration (C) is defined as the number of moles of solute divided by the volume of the solution in liters.

Molar concentration of H2SO4 (C) = number of moles of H2SO4 / final volume of the solution

C = 0.0988 mol / 0.2 L
= 0.494 M

Therefore, the molar concentration of H2SO4 in the dilute solution is 0.494 M.

Explanation:
- The number of moles of Mg is calculated using its molar mass.
- Since the stoichiometric ratio between Mg and H2SO4 is 1:1, the number of moles of H2SO4 is the same as that of Mg.
- The final volume of the solution is given as 200 mL, which is converted to liters.
- The molar concentration is then calculated by dividing the number of moles of H2SO4 by the final volume of the solution in liters.