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 LCALL instruction takes
  • a)
    2 bytes
  • b)
    4 bytes
  • c)
    3 bytes
  • d)
    1 byte
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
LCALL instruction takesa)2 bytesb)4 bytesc)3 bytesd)1 byteCorrect answ...
LCALL instruction moves the pointer to a 16 bit address so it is a 3 byte instruction.
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Most Upvoted Answer
LCALL instruction takesa)2 bytesb)4 bytesc)3 bytesd)1 byteCorrect answ...
The LCALL instruction in computer programming is used to call a subroutine or a function located at a specific memory address. This instruction is commonly found in assembly language programming.

Explanation:
The LCALL instruction is a 3-byte instruction. Let's break down the components of this instruction:

1. Opcode (1 byte): The opcode is the machine code representation of the LCALL instruction. It specifies that the instruction is a subroutine call. In most assembly languages, the opcode for LCALL is a specific hexadecimal value.

2. Address (2 bytes): The address component of the LCALL instruction specifies the memory address where the subroutine or function is located. This address is typically given as a hexadecimal value and requires 2 bytes of memory to represent it.

Since the opcode and address together make up the LCALL instruction, we can conclude that it is a 3-byte instruction.

It's important to note that the size of an instruction can vary depending on the specific architecture and assembly language being used. In some cases, an instruction may be encoded in fewer or more bytes. However, for the LCALL instruction, it is generally accepted that it is a 3-byte instruction.

In summary, the LCALL instruction is a 3-byte instruction in assembly language programming. It consists of a 1-byte opcode and a 2-byte address component. This instruction is used to call a subroutine or function located at a specific memory address.
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LCALL instruction takesa)2 bytesb)4 bytesc)3 bytesd)1 byteCorrect answer is option 'C'. Can you explain this answer?
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