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The car A of mass 1500kg travelling at 25ms^-2 collides with another carB of mass 1000kg travelling at 15ms^-2 in the same direction . After collision the velocity of car A becomes 20ms^-2. Calculate the velocity of car B after collision?
Most Upvoted Answer
The car A of mass 1500kg travelling at 25ms^-2 collides with another c...
M= mass
u= initial velocity
v= final velocity
A
m=1500
u=25
m*u=37500 (initial momentum of A)
v=20
m*v=30000 (final momentum of A)
B
m=1000
u=15
m*u=15000 (initial momentum of B)
- By conservation of linear momentum
m*u of A and m*u of B = m*v of A + m*v of V
37500 + 15000 = 30000 + m*v of B
52500 = 30000 + m*v of B
m*v of B = 52500 - 30000
m*v of B = 22500
v of B = 22500÷ 1000
v of B = 22.5 m/s
u= initial velocity
v= final velocity
A
m=1500
u=25
m*u=37500 (initial momentum of A)
v=20
m*v=30000 (final momentum of A)
B
m=1000
u=15
m*u=15000 (initial momentum of B)
- By conservation of linear momentum
m*u of A and m*u of B = m*v of A + m*v of V
37500 + 15000 = 30000 + m*v of B
52500 = 30000 + m*v of B
m*v of B = 52500 - 30000
m*v of B = 22500
v of B = 22500÷ 1000
v of B = 22.5 m/s
Community Answer
The car A of mass 1500kg travelling at 25ms^-2 collides with another c...
Given data:
Mass of car A (m1) = 1500 kg
Initial velocity of car A (u1) = 25 m/s
Mass of car B (m2) = 1000 kg
Initial velocity of car B (u2) = 15 m/s
Final velocity of car A (v1) = 20 m/s
Explanation:
To find the velocity of car B after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
Step 1: Calculate the momentum before the collision:
The momentum (p) of an object is given by the product of its mass (m) and velocity (v):
Momentum (p) = mass (m) × velocity (v)
The momentum of car A before the collision (p1) can be calculated as:
p1 = m1 × u1
The momentum of car B before the collision (p2) can be calculated as:
p2 = m2 × u2
Step 2: Calculate the momentum after the collision:
The momentum of car A after the collision (p1') can be calculated as:
p1' = m1 × v1
The momentum of car B after the collision (p2') can be calculated as:
p2' = m2 × v2
Step 3: Apply the principle of conservation of momentum:
According to the principle of conservation of momentum, the total momentum before the collision (p1 + p2) is equal to the total momentum after the collision (p1' + p2').
p1 + p2 = p1' + p2'
Substituting the values, we get:
m1 × u1 + m2 × u2 = m1 × v1 + m2 × v2
Step 4: Solve the equation for v2:
Rearranging the equation, we get:
m2 × u2 - m2 × v2 = m1 × v1 - m1 × u1
m2 × (u2 - v2) = m1 × (v1 - u1)
v2 = (m1 × (v1 - u1))/(m2)
Substituting the given values, we get:
v2 = (1500 × (20 - 25))/(1000)
Simplifying the equation, we get:
v2 = (1500 × -5)/(1000)
v2 = -7.5 m/s
Conclusion:
The velocity of car B after the collision is -7.5 m/s. The negative sign indicates that car B is moving in the opposite direction to its initial velocity.
Mass of car A (m1) = 1500 kg
Initial velocity of car A (u1) = 25 m/s
Mass of car B (m2) = 1000 kg
Initial velocity of car B (u2) = 15 m/s
Final velocity of car A (v1) = 20 m/s
Explanation:
To find the velocity of car B after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
Step 1: Calculate the momentum before the collision:
The momentum (p) of an object is given by the product of its mass (m) and velocity (v):
Momentum (p) = mass (m) × velocity (v)
The momentum of car A before the collision (p1) can be calculated as:
p1 = m1 × u1
The momentum of car B before the collision (p2) can be calculated as:
p2 = m2 × u2
Step 2: Calculate the momentum after the collision:
The momentum of car A after the collision (p1') can be calculated as:
p1' = m1 × v1
The momentum of car B after the collision (p2') can be calculated as:
p2' = m2 × v2
Step 3: Apply the principle of conservation of momentum:
According to the principle of conservation of momentum, the total momentum before the collision (p1 + p2) is equal to the total momentum after the collision (p1' + p2').
p1 + p2 = p1' + p2'
Substituting the values, we get:
m1 × u1 + m2 × u2 = m1 × v1 + m2 × v2
Step 4: Solve the equation for v2:
Rearranging the equation, we get:
m2 × u2 - m2 × v2 = m1 × v1 - m1 × u1
m2 × (u2 - v2) = m1 × (v1 - u1)
v2 = (m1 × (v1 - u1))/(m2)
Substituting the given values, we get:
v2 = (1500 × (20 - 25))/(1000)
Simplifying the equation, we get:
v2 = (1500 × -5)/(1000)
v2 = -7.5 m/s
Conclusion:
The velocity of car B after the collision is -7.5 m/s. The negative sign indicates that car B is moving in the opposite direction to its initial velocity.
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The car A of mass 1500kg travelling at 25ms^-2 collides with another carB of mass 1000kg travelling at 15ms^-2 in the same direction . After collision the velocity of car A becomes 20ms^-2. Calculate the velocity of car B after collision?
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The car A of mass 1500kg travelling at 25ms^-2 collides with another carB of mass 1000kg travelling at 15ms^-2 in the same direction . After collision the velocity of car A becomes 20ms^-2. Calculate the velocity of car B after collision? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The car A of mass 1500kg travelling at 25ms^-2 collides with another carB of mass 1000kg travelling at 15ms^-2 in the same direction . After collision the velocity of car A becomes 20ms^-2. Calculate the velocity of car B after collision? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The car A of mass 1500kg travelling at 25ms^-2 collides with another carB of mass 1000kg travelling at 15ms^-2 in the same direction . After collision the velocity of car A becomes 20ms^-2. Calculate the velocity of car B after collision?.
The car A of mass 1500kg travelling at 25ms^-2 collides with another carB of mass 1000kg travelling at 15ms^-2 in the same direction . After collision the velocity of car A becomes 20ms^-2. Calculate the velocity of car B after collision? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The car A of mass 1500kg travelling at 25ms^-2 collides with another carB of mass 1000kg travelling at 15ms^-2 in the same direction . After collision the velocity of car A becomes 20ms^-2. Calculate the velocity of car B after collision? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The car A of mass 1500kg travelling at 25ms^-2 collides with another carB of mass 1000kg travelling at 15ms^-2 in the same direction . After collision the velocity of car A becomes 20ms^-2. Calculate the velocity of car B after collision?.
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