Class 12 Exam > Class 12 Questions > The correct statement isa)[Ni(NH3)6]2+ is an ...
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The correct statement is
- a)[Ni(NH3)6]2+ is an inner orbital complex
- b)[CrBr2(en)2)- exhibits linkage isomerism
- c)[MnBr4]2- is tetrahedral
- d)[Co(NH3)6]3+ is paramagnetic
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[C...
[MnBr4]2- is tetrahedral complex.
Most Upvoted Answer
The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[C...
The correct statement is option 'C': [MnBr4]2- is tetrahedral.
Explanation:
[MnBr4]2- is a coordination complex in which the central metal ion is manganese (Mn) and it is surrounded by four bromide (Br-) ligands. To determine the geometry of the complex, we need to consider the electron pair geometry and the number of bonding and non-bonding electron pairs around the central metal ion.
1. Electron pair geometry:
The electron pair geometry of [MnBr4]2- can be determined by considering the number of electron pairs around the central metal ion. In this case, there are four bromide ligands, each contributing one electron pair. So, there are four electron pairs around the central metal ion. The electron pair geometry corresponding to four electron pairs is tetrahedral.
2. Molecular geometry:
The molecular geometry of [MnBr4]2- can be determined by considering the number of bonding and non-bonding electron pairs around the central metal ion. In this case, all four bromide ligands are bonded to the central metal ion, so there are four bonding electron pairs. There are no non-bonding electron pairs since there are no lone pairs on the central metal ion. The molecular geometry corresponding to four bonding electron pairs is also tetrahedral.
Therefore, the correct statement is that [MnBr4]2- is tetrahedral in shape.
Explanation:
[MnBr4]2- is a coordination complex in which the central metal ion is manganese (Mn) and it is surrounded by four bromide (Br-) ligands. To determine the geometry of the complex, we need to consider the electron pair geometry and the number of bonding and non-bonding electron pairs around the central metal ion.
1. Electron pair geometry:
The electron pair geometry of [MnBr4]2- can be determined by considering the number of electron pairs around the central metal ion. In this case, there are four bromide ligands, each contributing one electron pair. So, there are four electron pairs around the central metal ion. The electron pair geometry corresponding to four electron pairs is tetrahedral.
2. Molecular geometry:
The molecular geometry of [MnBr4]2- can be determined by considering the number of bonding and non-bonding electron pairs around the central metal ion. In this case, all four bromide ligands are bonded to the central metal ion, so there are four bonding electron pairs. There are no non-bonding electron pairs since there are no lone pairs on the central metal ion. The molecular geometry corresponding to four bonding electron pairs is also tetrahedral.
Therefore, the correct statement is that [MnBr4]2- is tetrahedral in shape.
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The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer?
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The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer?.
The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The correct statement isa)[Ni(NH3)6]2+ is an inner orbital complexb)[CrBr2(en)2)-exhibits linkage isomerismc)[MnBr4]2-is tetrahedrald)[Co(NH3)6]3+ is paramagneticCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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