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A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t = 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :
- a)It goes HIGH at t = 0 and back LOW at t = 3 ms
- b)It goes HIGH at t = 0 and back LOW at t = 1 ms
- c)It goes HIGH at t = 0 and back LOW at t = 0.8 ms
- d)It goes HIGH at t = 1 ms and back LOW at t = 3 ms
Correct answer is option 'C,D'. Can you explain this answer?
Verified Answer
A pulse is applied to each input of an exclusive OR gate. One pulse go...
Output is HIGH when only one of the input is high.
The correct answers are: It goes HIGH at t = 0 and back LOW at t = 0.8 ms, It goes HIGH at t = 1 ms and back LOW at t = 3 ms
The correct answers are: It goes HIGH at t = 0 and back LOW at t = 0.8 ms, It goes HIGH at t = 1 ms and back LOW at t = 3 ms
Most Upvoted Answer
A pulse is applied to each input of an exclusive OR gate. One pulse go...
Explanation:
An exclusive OR (XOR) gate is a digital logic gate that outputs true (HIGH) when the number of true inputs is odd. In other words, it produces a HIGH output if the number of HIGH inputs is an odd number.
In this scenario, we have two pulses applied to the inputs of the XOR gate. Let's analyze each input pulse and determine the resulting output pulse.
Input Pulse 1:
- Goes HIGH at t = 0 and back LOW at t = 1 ms
Input Pulse 2:
- Goes HIGH at t = 0.8 ms and back LOW at t = 3 ms
Now, let's consider the time intervals for each pulse and determine the resulting output pulse.
Time Intervals:
- t = 0 to t = 0.8 ms (Input Pulse 1 is HIGH, Input Pulse 2 is LOW)
- t = 0.8 ms to t = 1 ms (Both Input Pulse 1 and Input Pulse 2 are HIGH)
- t = 1 ms to t = 3 ms (Input Pulse 1 is LOW, Input Pulse 2 is HIGH)
- t = 3 ms onwards (Both Input Pulse 1 and Input Pulse 2 are LOW)
Output Pulse:
- The output pulse of an XOR gate is HIGH when the number of HIGH inputs is odd.
- In the time interval t = 0 to t = 0.8 ms, only Input Pulse 1 is HIGH, so the output remains LOW.
- In the time interval t = 0.8 ms to t = 1 ms, both Input Pulse 1 and Input Pulse 2 are HIGH, so the output becomes HIGH.
- In the time interval t = 1 ms to t = 3 ms, only Input Pulse 2 is HIGH, so the output remains HIGH.
- After t = 3 ms, both Input Pulse 1 and Input Pulse 2 are LOW, so the output becomes LOW.
Therefore, the output pulse goes HIGH at t = 0 and back LOW at t = 1 ms, and then goes HIGH again at t = 0.8 ms and back LOW at t = 3 ms. Hence, the correct answer is option 'C,D'.
An exclusive OR (XOR) gate is a digital logic gate that outputs true (HIGH) when the number of true inputs is odd. In other words, it produces a HIGH output if the number of HIGH inputs is an odd number.
In this scenario, we have two pulses applied to the inputs of the XOR gate. Let's analyze each input pulse and determine the resulting output pulse.
Input Pulse 1:
- Goes HIGH at t = 0 and back LOW at t = 1 ms
Input Pulse 2:
- Goes HIGH at t = 0.8 ms and back LOW at t = 3 ms
Now, let's consider the time intervals for each pulse and determine the resulting output pulse.
Time Intervals:
- t = 0 to t = 0.8 ms (Input Pulse 1 is HIGH, Input Pulse 2 is LOW)
- t = 0.8 ms to t = 1 ms (Both Input Pulse 1 and Input Pulse 2 are HIGH)
- t = 1 ms to t = 3 ms (Input Pulse 1 is LOW, Input Pulse 2 is HIGH)
- t = 3 ms onwards (Both Input Pulse 1 and Input Pulse 2 are LOW)
Output Pulse:
- The output pulse of an XOR gate is HIGH when the number of HIGH inputs is odd.
- In the time interval t = 0 to t = 0.8 ms, only Input Pulse 1 is HIGH, so the output remains LOW.
- In the time interval t = 0.8 ms to t = 1 ms, both Input Pulse 1 and Input Pulse 2 are HIGH, so the output becomes HIGH.
- In the time interval t = 1 ms to t = 3 ms, only Input Pulse 2 is HIGH, so the output remains HIGH.
- After t = 3 ms, both Input Pulse 1 and Input Pulse 2 are LOW, so the output becomes LOW.
Therefore, the output pulse goes HIGH at t = 0 and back LOW at t = 1 ms, and then goes HIGH again at t = 0.8 ms and back LOW at t = 3 ms. Hence, the correct answer is option 'C,D'.
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A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer?
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A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer?.
A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer?.
Solutions for A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
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Here you can find the meaning of A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer?, a detailed solution for A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? has been provided alongside types of A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A pulse is applied to each input of an exclusive OR gate. One pulse goes HIGH at t = 0 and goes back LOW at t = 1 ms. The other pulse goes HIGH at t= 0.8 ms and goes back LOW at t = 3 ms. The output pulse can be described as follows :a)It goes HIGH at t = 0 and back LOW at t = 3 msb)It goes HIGH at t = 0 and back LOW at t = 1 msc)It goes HIGH at t = 0 and back LOW at t = 0.8msd)It goes HIGH at t = 1 msand back LOW at t = 3 msCorrect answer is option 'C,D'. Can you explain this answer? tests, examples and also practice Physics tests.
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