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Calculate the force between two charges having magnitude 3nC and 2nC separated by a distance of 2micro m.
  • a)
    13.5N
  • b)
    13.5kN
  • c)
    1.35N
  • d)
    1.35kN
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Calculate the force between two charges having magnitude 3nC and 2nC s...
From the expression:
F=Kq1q2/r2, the value of K being 9*109, we get F=13.5kN.
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Most Upvoted Answer
Calculate the force between two charges having magnitude 3nC and 2nC s...
Given:
- Charge 1 magnitude = 3 nC
- Charge 2 magnitude = 2 nC
- Distance between the charges = 2 µm

To calculate the force between the charges, we can use Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

Coulomb's law equation:
F = (k * q1 * q2) / r^2

where:
- F is the force between the charges
- k is the electrostatic constant (k = 9 * 10^9 Nm^2/C^2)
- q1 is the magnitude of charge 1
- q2 is the magnitude of charge 2
- r is the distance between the charges

Let's substitute the given values into the equation:

F = (9 * 10^9 Nm^2/C^2) * ((3 * 10^-9 C) * (2 * 10^-9 C)) / (2 * 10^-6 m)^2

Simplifying the equation:

F = (9 * 3 * 2 * 10^-18) / 4 * 10^-12

F = 54 * 10^-18 / 4 * 10^-12

F = 13.5 * 10^-6 N

Converting the result to kilonewtons (kN):

F = 13.5 * 10^-6 N = 13.5 * 10^-6 * 10^-3 kN

F = 13.5 * 10^-9 kN

Therefore, the force between the charges is 13.5 kN.
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