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A body of mass m hits normally a rigid Wall with velocity v and bounces back with the same velocity . The impulse experienced by the body is?
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A body of mass m hits normally a rigid Wall with velocity v and bounce...
Impulse:
Impulse is defined as the change in momentum of an object when a force is applied to it for a certain amount of time. Mathematically, impulse can be calculated using the formula:

Impulse = Change in Momentum

Explanation:

1. Initial momentum:
When the body of mass m hits the wall with velocity v, its initial momentum is given by:

Initial momentum = mass x velocity = m x v

2. Final momentum:
After bouncing back, the body still has the same velocity v, but in the opposite direction. Therefore, its final momentum is given by:

Final momentum = mass x final velocity = m x (-v) = -m x v

3. Change in momentum:
The change in momentum of the body is the difference between its final and initial momentum. In this case, it is given by:

Change in momentum = Final momentum - Initial momentum = (-m x v) - (m x v) = -2m x v

4. Impulse:
The impulse experienced by the body is equal to the change in momentum. Therefore, the impulse is:

Impulse = Change in momentum = -2m x v

The negative sign indicates that the impulse is in the opposite direction to the initial momentum of the body.

Conclusion:
When a body of mass m hits a rigid wall with velocity v and bounces back with the same velocity, the impulse experienced by the body is -2m x v. This impulse is in the opposite direction to the initial momentum of the body.
Community Answer
A body of mass m hits normally a rigid Wall with velocity v and bounce...
Answer is 2mv hence , mv- ( - mv ) = 2mv
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A body of mass m hits normally a rigid Wall with velocity v and bounces back with the same velocity . The impulse experienced by the body is?
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