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A body starts moving with a velocity v'=10m/s. It experiences a retardation equal to 0.2v^2. its velocity after 2 seconds is given by?
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A body starts moving with a velocity v'=10m/s. It experiences a retard...
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A body starts moving with a velocity v'=10m/s. It experiences a retard...
Calculation of Velocity of a Body


Given Data


  • Initial Velocity (v') = 10 m/s

  • Retardation (a) = 0.2v^2

  • Time (t) = 2 seconds



Calculation

Retardation (a) = 0.2v^2

Using the formula of acceleration (a) = (v - u)/t, where


  • v = final velocity

  • u = initial velocity

  • t = time



Substituting the given values and the formula for retardation, we get:


0.2v^2 = (v - 10)/2

0.4v^2 - v + 10 = 0


Using the quadratic formula, we can find the value of v:


v = (1 ± sqrt(1 - 4*0.4*10))/0.8

v = (1 ± sqrt(-15))/0.8

Since the value inside the square root is negative, there are no real solutions.


Conclusion

Therefore, the velocity of the body after 2 seconds cannot be calculated since the value inside the square root is negative, and there are no real solutions.
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A body starts moving with a velocity v'=10m/s. It experiences a retardation equal to 0.2v^2. its velocity after 2 seconds is given by?
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