Explanation:


Step 1: Find the possible isomers of the complex


Step 2: Determine if each isomer is chiral or not


Step 3: Calculate the total number of stereoisomers using the formula 2^n, where n is the number of chiral isomers



Step 1: Find the possible isomers of the complex


Pt(gly)2Cl2 can form four different isomers based on the position of the two glycine molecules and the two chloride ions. These are:


- cis-cis (both glycine molecules and both chloride ions are on the same side of the Pt atom)


- cis-trans (one glycine molecule and one chloride ion are on one side of the Pt atom, and the other glycine molecule and chloride ion are on the other side)


- trans-cis (the opposite of cis-trans)


- trans-trans (both glycine molecules and both chloride ions are on opposite sides of the Pt atom)

Step 2: Determine if each isomer is chiral or not


A complex is chiral if it does not have a plane of symmetry. The cis-cis and trans-trans isomers of Pt(gly)2Cl2 are achiral because they have a plane of symmetry. The cis-trans and trans-cis isomers are chiral because they do not have a plane of symmetry.

Step 3: Calculate the total number of stereoisomers using the formula 2^n, where n is the number of chiral isomers


Since there are two chiral isomers (cis-trans and trans-cis), the total number of stereoisomers is 2^2 = 4. However, each chiral isomer can exist as a pair of enantiomers, which are mirror images of each other. Therefore, the total number of stereoisomers is 4 x 2 = 8.

Answer: Therefore, there are 8 stereoisomers of Pt(gly)2Cl2.