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Transition metals are often paramagnetic owing to- 
  • a)
    High Melting point and Boiling Point
  • b)
    The presence of vacant orbitals 
  • c)
    The presence of unpaired electrons  
  • d)
    Malleability and ductility 
Correct answer is option 'C'. Can you explain this answer?
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Transition metals are often paramagnetic owing to-a)High Melting point...
Transition elements containing one or more unpaired electrons show paramagnetic behavior where the effects of individual electrons are not mutually compensated. The magnetic moment due to unpaired electron spins is aligned parallel to the external magnetic field more effectively.
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Transition metals are often paramagnetic owing to-a)High Melting point...
Paramagnetic Nature of Transition Metals

Transition metals are often paramagnetic due to the presence of unpaired electrons in their d orbitals.

Presence of Unpaired Electrons
- Transition metals have partially filled d orbitals, which can accommodate unpaired electrons.
- These unpaired electrons give rise to magnetic moments, making the metals paramagnetic.

Magnetic Properties
- Paramagnetic materials are weakly attracted to magnetic fields.
- The presence of unpaired electrons in transition metals causes them to exhibit paramagnetic behavior.

Explanation
- When a magnetic field is applied, the unpaired electrons align their spins with the field, resulting in a net magnetic moment.
- This alignment leads to weak attraction to the external magnetic field, characteristic of paramagnetic materials.

Significance
- The paramagnetic nature of transition metals is essential in various applications like magnetic data storage, MRI machines, and catalysts.

In conclusion, the paramagnetic nature of transition metals is primarily attributed to the presence of unpaired electrons in their d orbitals. This property distinguishes them from other elements and contributes to their unique magnetic behavior.
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Transition metals are often paramagnetic owing to-a)High Melting point...
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Transition metals are often paramagnetic owing to-a)High Melting point and Boiling Pointb)The presence of vacant orbitalsc)The presence of unpaired electronsd)Malleability and ductilityCorrect answer is option 'C'. Can you explain this answer?
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