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A crank slotted lever mechanism used in a shaper has a centre distance of 500 mm between the centre of oscillation of the slotted lever and the center of rotation of the crank. The radius of crank is 250 mm. The ratio of cutting stroke to return stroke time is _________.
  • a)
     2
  • b)
     5
  • c)
     5.57
  • d)
     12
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A crank slotted lever mechanism used in a shaper has a centre distance...


= 60 X 2 = 1200



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Most Upvoted Answer
A crank slotted lever mechanism used in a shaper has a centre distance...
Given data:
Centre distance between the centre of oscillation of the slotted lever and the center of rotation of the crank = 500 mm
Radius of crank = 250 mm

We know that the cutting stroke time = π/2√(a/g)
where a = acceleration of the slider
g = acceleration due to gravity

Also, return stroke time = π/2√((2r-a)/g)

Ratio of cutting stroke to return stroke time = (π/2√(a/g))/(π/2√((2r-a)/g))
= √((2r-a)/a)

Now, we need to find the value of 'a' to calculate the ratio.

a = (ω² × r) / g
where ω = angular velocity of the crank

We can calculate ω using the formula:
ω = (2π × n) / 60
where n = speed of the crank in rpm

Assuming n = 60 rpm, we get
ω = (2π × 60) / 60 = 2π rad/s

Substituting the values of ω, r and g, we get
a = (2π)² × 0.25 / 9.81 = 3.99 m/s²

Now, substituting the value of 'a' in the formula for ratio, we get
Ratio of cutting stroke to return stroke time = √((2r-a)/a) = √((2 × 0.25 - 3.99) / 3.99)
≈ 2

Therefore, the ratio of cutting stroke to return stroke time is 2.
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A crank slotted lever mechanism used in a shaper has a centre distance of 500 mm between the centre of oscillation of the slotted lever and the center of rotation of the crank. The radius of crank is 250 mm. The ratio of cutting stroke to return stroke time is _________.a)2b)5c)5.57d)12Correct answer is option 'A'. Can you explain this answer?
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