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Acetamide is treated separately with the following reagents. Which of these would give methylamine ?
  • a)
    PCl5
  • b)
    Sodalime
  • c)
    NaOH + Br2
  • d)
    Hot, conc. H2SO4
Correct answer is option 'C'. Can you explain this answer?
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Acetamide is treated separately with the following reagents. Which of ...
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Acetamide is treated separately with the following reagents. Which of ...
Answer:
To obtain methylamine from acetamide, we need to convert the amide functional group (-CONH2) into an amine functional group (-NH2). This can be achieved by treating acetamide with sodium hydroxide (NaOH).

Explanation:
Step 1: Hydrolysis of Acetamide
When acetamide is treated with NaOH, it undergoes hydrolysis to form sodium acetate and ammonia gas.

Acetamide + NaOH → Sodium Acetate + Ammonia

The reaction can be represented as:
CH3CONH2 + NaOH → CH3COONa + NH3

Step 2: Formation of Methylamine
The ammonia gas produced in the hydrolysis step can be further treated with excess NaOH to form methylamine.

NH3 + NaOH → CH3NH2 + H2O

Conclusion:
Hence, when acetamide is treated with NaOH, it undergoes hydrolysis to form sodium acetate and ammonia. The ammonia is then further reacted with excess NaOH to give methylamine. Therefore, option C (NaOH) is the correct answer.
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