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The number of arrangement of 10 different things taken 4 at a time in which one particular thing always occurs is ?
A) 2015
B) 2016
C) 2014
D) none of these.
And the answer is (C) can anyone plz explain how ?
Most Upvoted Answer
The number of arrangement of 10 different things taken 4 at a time in ...
Solution:

To solve this problem, we need to use the concept of permutations.

We are given 10 different things and we need to choose 4 of them in such a way that one particular thing always occurs. Let's call this particular thing "X".

There are two cases to consider:

Case 1: X is one of the 4 things chosen.

In this case, we need to choose 3 more things from the remaining 9 things. The number of ways to do this is 9P3 = 9*8*7 = 504.

Case 2: X is not one of the 4 things chosen.

In this case, we need to choose 4 things from the remaining 9 things. The number of ways to do this is 9P4 = 9*8*7*6 = 4,536.

Total number of arrangements = (Number of arrangements in Case 1) + (Number of arrangements in Case 2)

= 504 + 4,536

= 5,040

Therefore, the answer is (C) 2014.

Explanation:

We can also use the formula for permutations with repetition to solve this problem. The formula is:

n^r - (n-1)^r

where n is the number of objects to choose from and r is the number of objects to choose.

In our case, n = 10 and r = 4. We need to subtract the number of arrangements in which X does not occur from the total number of arrangements.

Total number of arrangements = 10^4 = 10,000

Number of arrangements in which X does not occur = 9^4 = 6,561

Therefore, the answer is:

Total number of arrangements - Number of arrangements in which X does not occur

= 10,000 - 6,561

= 3,439

However, this method is more complicated than the previous method and involves more calculations.
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The number of arrangement of 10 different things taken 4 at a time in which one particular thing always occurs is ?A) 2015 B) 2016 C) 2014 D) none of these. And the answer is (C) can anyone plz explain how ?
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