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The input to a linear delta modulator having fa step-size Δ = 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs = 40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place is
- a)Em = 0.3V , fm = 8KHz
- b)Em = 1.5V , fm = 4kHz
- c)Em = 1.5 V , fm = 2kHz
- d)Em = 3.0V , fm = 1kHZ
Correct answer is option 'B'. Can you explain this answer?
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The input to a linear delta modulator having fastep-size Δ= 0.628...
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The input to a linear delta modulator having fastep-size Δ= 0.628...
Linear Delta Modulation and Slope Overload
Linear Delta Modulation (LDM) is a type of analog-to-digital conversion technique used in communication systems. It is a variant of Delta Modulation (DM) in which the quantization step size is fixed and linearly proportional to the amplitude of the input signal.
Slope Overload is a phenomenon that occurs in LDM when the amplitude of the input signal exceeds the maximum permissible slope of the quantization step. This leads to distortion and errors in the output signal.
Given Parameters
In this question, we are given the following parameters:
- Fast step-size = 0.628
- Sampling frequency fs = 40 kHz
- Input signal = sine wave with frequency fm and peak amplitude Em
We need to determine the combination of frequency fm and peak amplitude Em, where slope overload will take place.
Solution Steps
To solve this problem, we need to use the formula for the maximum permissible slope of the LDM quantization step:
Smax = 2 * δ * fs
where Smax is the maximum permissible slope, δ is the fast step-size, and fs is the sampling frequency.
We know that the input signal is a sine wave with frequency fm and peak amplitude Em. Therefore, its maximum slope is given by:
S = Em * 2π * fm
To avoid slope overload, we need to ensure that Smax > S. Substituting the given values, we get:
2 * δ * fs > Em * 2π * fm
Simplifying, we get:
Em/fm < (2="" *="" δ="" *="" fs)="" />
Substituting the given values, we get:
Em/fm < (2="" *="" 0.628="" *="" 40,000)="" />
Em/fm < />
Therefore, the combination of frequency fm and peak amplitude Em, where slope overload will take place, is:
Em = 1.5 V, fm = 4 kHz
Option B is the correct answer.
Conclusion
In this question, we have learned about Linear Delta Modulation and Slope Overload. We have solved a numerical problem to determine the combination of frequency and amplitude where slope overload will occur in an LDM system.
Linear Delta Modulation (LDM) is a type of analog-to-digital conversion technique used in communication systems. It is a variant of Delta Modulation (DM) in which the quantization step size is fixed and linearly proportional to the amplitude of the input signal.
Slope Overload is a phenomenon that occurs in LDM when the amplitude of the input signal exceeds the maximum permissible slope of the quantization step. This leads to distortion and errors in the output signal.
Given Parameters
In this question, we are given the following parameters:
- Fast step-size = 0.628
- Sampling frequency fs = 40 kHz
- Input signal = sine wave with frequency fm and peak amplitude Em
We need to determine the combination of frequency fm and peak amplitude Em, where slope overload will take place.
Solution Steps
To solve this problem, we need to use the formula for the maximum permissible slope of the LDM quantization step:
Smax = 2 * δ * fs
where Smax is the maximum permissible slope, δ is the fast step-size, and fs is the sampling frequency.
We know that the input signal is a sine wave with frequency fm and peak amplitude Em. Therefore, its maximum slope is given by:
S = Em * 2π * fm
To avoid slope overload, we need to ensure that Smax > S. Substituting the given values, we get:
2 * δ * fs > Em * 2π * fm
Simplifying, we get:
Em/fm < (2="" *="" δ="" *="" fs)="" />
Substituting the given values, we get:
Em/fm < (2="" *="" 0.628="" *="" 40,000)="" />
Em/fm < />
Therefore, the combination of frequency fm and peak amplitude Em, where slope overload will take place, is:
Em = 1.5 V, fm = 4 kHz
Option B is the correct answer.
Conclusion
In this question, we have learned about Linear Delta Modulation and Slope Overload. We have solved a numerical problem to determine the combination of frequency and amplitude where slope overload will occur in an LDM system.
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Question Description
The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer?.
The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
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The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The input to a linear delta modulator having fastep-size Δ= 0.628 is a sine wave with frequency fm and peak amplitude Em. If the sampling frequency fs=40 kHz, the combination of the sinc-wave frequency and the peak amplitude, where slope overload will take place isa)Em= 0.3V , fm= 8KHzb)Em= 1.5V, fm= 4kHzc)Em=1.5 V , fm= 2kHzd)Em= 3.0V , fm= 1kHZCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
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