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Which of the following arrangements gives the correct order of increasing oxidation number of iodine?
- a)I2 < HI < ICI < HIO4
- b)HI < ICI < I2 < HIO4
- c)ICI < HI < HIO4< I2
- d)HI < I2< ICI < HIO4
Correct answer is option 'D'. Can you explain this answer?
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Correct answer: Option D
To determine the correct order of increasing oxidation number of iodine in the given arrangements, we need to understand the concept of oxidation numbers and how they change in different compounds.
Oxidation number is the hypothetical charge that an atom would have if all bonds in a compound were 100% ionic. It is a useful tool for keeping track of electron transfers during chemical reactions.
In the given arrangements, we have the following compounds:
a) I2, HI, ICI, HIO4
b) HI, ICI, I2, HIO4
c) ICI, HI, HIO4, I2
d) HI, I2, ICI, HIO4
Explanation:
In order to determine the oxidation number of iodine in each compound, we need to consider the following rules:
1. The oxidation number of a free element is always zero.
2. The oxidation number of a monatomic ion is equal to its charge.
3. In compounds, the oxidation number of hydrogen is usually +1, and the oxidation number of oxygen is usually -2.
4. The sum of the oxidation numbers in a neutral compound is zero, and it is equal to the charge of the compound in an ion.
Now, let's analyze each compound in the given arrangements and determine the oxidation number of iodine:
a) I2: The oxidation number of a free element is always zero.
HI: Hydrogen usually has an oxidation number of +1.
ICI: Since the total oxidation number of a compound is zero, and hydrogen has an oxidation number of +1, we can deduce that iodine in ICI has an oxidation number of +1.
HIO4: Oxygen usually has an oxidation number of -2, and since the total oxidation number of the compound is zero, iodine in HIO4 has an oxidation number of +7.
b) HI: Hydrogen usually has an oxidation number of +1.
ICI: Since the total oxidation number of a compound is zero, and hydrogen has an oxidation number of +1, we can deduce that iodine in ICI has an oxidation number of +1.
I2: The oxidation number of a free element is always zero.
HIO4: Oxygen usually has an oxidation number of -2, and since the total oxidation number of the compound is zero, iodine in HIO4 has an oxidation number of +7.
c) ICI: Since the total oxidation number of a compound is zero, and hydrogen has an oxidation number of +1, we can deduce that iodine in ICI has an oxidation number of +1.
HI: Hydrogen usually has an oxidation number of +1.
HIO4: Oxygen usually has an oxidation number of -2, and since the total oxidation number of the compound is zero, iodine in HIO4 has an oxidation number of +7.
I2: The oxidation number of a free element is always zero.
d) HI: Hydrogen usually has an oxidation number of +1.
I2: The oxidation number of a free element is always zero.
ICI: Since the total oxidation number of a compound is zero, and hydrogen has an oxidation number of +1, we can deduce that iodine in ICI has an oxidation number of +1.
To determine the correct order of increasing oxidation number of iodine in the given arrangements, we need to understand the concept of oxidation numbers and how they change in different compounds.
Oxidation number is the hypothetical charge that an atom would have if all bonds in a compound were 100% ionic. It is a useful tool for keeping track of electron transfers during chemical reactions.
In the given arrangements, we have the following compounds:
a) I2, HI, ICI, HIO4
b) HI, ICI, I2, HIO4
c) ICI, HI, HIO4, I2
d) HI, I2, ICI, HIO4
Explanation:
In order to determine the oxidation number of iodine in each compound, we need to consider the following rules:
1. The oxidation number of a free element is always zero.
2. The oxidation number of a monatomic ion is equal to its charge.
3. In compounds, the oxidation number of hydrogen is usually +1, and the oxidation number of oxygen is usually -2.
4. The sum of the oxidation numbers in a neutral compound is zero, and it is equal to the charge of the compound in an ion.
Now, let's analyze each compound in the given arrangements and determine the oxidation number of iodine:
a) I2: The oxidation number of a free element is always zero.
HI: Hydrogen usually has an oxidation number of +1.
ICI: Since the total oxidation number of a compound is zero, and hydrogen has an oxidation number of +1, we can deduce that iodine in ICI has an oxidation number of +1.
HIO4: Oxygen usually has an oxidation number of -2, and since the total oxidation number of the compound is zero, iodine in HIO4 has an oxidation number of +7.
b) HI: Hydrogen usually has an oxidation number of +1.
ICI: Since the total oxidation number of a compound is zero, and hydrogen has an oxidation number of +1, we can deduce that iodine in ICI has an oxidation number of +1.
I2: The oxidation number of a free element is always zero.
HIO4: Oxygen usually has an oxidation number of -2, and since the total oxidation number of the compound is zero, iodine in HIO4 has an oxidation number of +7.
c) ICI: Since the total oxidation number of a compound is zero, and hydrogen has an oxidation number of +1, we can deduce that iodine in ICI has an oxidation number of +1.
HI: Hydrogen usually has an oxidation number of +1.
HIO4: Oxygen usually has an oxidation number of -2, and since the total oxidation number of the compound is zero, iodine in HIO4 has an oxidation number of +7.
I2: The oxidation number of a free element is always zero.
d) HI: Hydrogen usually has an oxidation number of +1.
I2: The oxidation number of a free element is always zero.
ICI: Since the total oxidation number of a compound is zero, and hydrogen has an oxidation number of +1, we can deduce that iodine in ICI has an oxidation number of +1.
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Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer?.
Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer?.
Solutions for Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Which of the following arrangements gives the correct order of increasing oxidation number of iodine?a)I2 < HI <ICI <HIO4b)HI <ICI <I2 < HIO4c)ICI <HI <HIO4< I2d)HI < I2< ICI < HIO4Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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